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fgiga [73]
4 years ago
6

Keisha is going on a trip. She can take some or all of the five novels from the list below with her. She must take at least one

of them. Ascent, Beloved, Catcher, Dune, Light In how many different ways can Keisha choose the novels to take with her? (The order the novels are chosen doesn't matter.)
Mathematics
1 answer:
Sonja [21]4 years ago
3 0

Answer:

there are multiple different ways figure it out yourself lol, JK the answer is Ascent, Catcher, Light, Beloved, and Dune

Step-by-step explanation:

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For which value of theta is cot (theta) undefined?
sattari [20]

The cotangent function is defined as the ratio between cosine and sine of a given angle, i.e.


\cot(x) = \frac{\cos(x)}{\sin(x)}


Since you can't have zero at the denominator, the cotangent function is not defined when the sine is zero.


Let's look at your option:


\sin(90^\circ) = 1, so the cotangent is defined here


\sin(180^\circ) = 0, so the cotangent is not defined here


\sin(270^\circ) = -1, so the cotangent is defined here


\sin(450^\circ) = \sin(360^\circ+90^\circ)=\sin(90^\circ) = 1, so the cotangent is defined here

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3 years ago
How many dimes is 5.60
OverLord2011 [107]

Answer:

56

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3 0
3 years ago
4TH TIME ASKING THIS!!! Please help me! Someone pleaseeee. I need the correct answers. I don’t want to fail
Alexeev081 [22]

Answer:

The functions are inverses; f(g(x)) = x ⇒ answer D

h^{-1}(x)=\sqrt{\frac{x+1}{3}} ⇒ answer D

Step-by-step explanation:

* <em>Lets explain how to find the inverse of a function</em>

- Let f(x) = y

- Exchange x and y

- Solve to find the new y

- The new y = f^{-1}(x)

* <em>Lets use these steps to solve the problems</em>

∵ f(x)=\sqrt{x-3}

∵ f(x) = y

∴ y=\sqrt{x-3}

- Exchange x and y

∴ x=\sqrt{y-3}

- Square the two sides

∴ x² = y - 3

- Add 3 to both sides

∴ x² + 3 = y

- Change y by f^{-1}(x)

∴ f^{-1}(x)=x^{2}+3

∵ g(x) = x² + 3

∴ f^{-1}(x)=g(x)

∴ <u><em>The functions are inverses to each other</em></u>

* <em>Now lets find f(g(x))</em>

- To find f(g(x)) substitute x in f(x) by g(x)

∵ f(x)=\sqrt{x-3}

∵ g(x) = x² + 3

∴ f(g(x))=\sqrt{(x^{2}+3)-3}=\sqrt{x^{2}+3-3}=\sqrt{x^{2}}=x

∴ <u><em>f(g(x)) = x</em></u>

∴ The functions are inverses; f(g(x)) = x

* <em>Lets find the inverse of h(x)</em>

∵ h(x) = 3x² - 1 where x ≥ 0

- Let h(x) = y

∴ y = 3x² - 1

- Exchange x and y

∴ x = 3y² - 1

- Add 1 to both sides

∴ x + 1 = 3y²

- Divide both sides by 3

∴ \frac{x + 1}{3}=y^{2}

- Take √ for both sides

∴ ± \sqrt{\frac{x+1}{3}}=y

∵ x ≥ 0

∴ We will chose the positive value of the square root

∴ \sqrt{\frac{x+1}{3}}=y

- replace y by h^{-1}(x)

∴ h^{-1}(x)=\sqrt{\frac{x+1}{3}}

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3 years ago
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timofeeve [1]
The distance might be the slope of the line
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