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3 years ago

Explain how drinking through a straw illustrates fluid flowing from high-pressure to low-pressure areas.

2 answers:

6 0

<span>the pressure in the straw is reduced, but the atmospeheric pressure on the surface of the liquid stays the same.</span>

PolarNik [594]3 years ago

5 0

The outside pressure forces the liquid up the straw and into your mouth. So, just by drinking through a straw, you can observe an important property of fluids. Fluids flow from areas of high pressure to areas of low pressure.

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In a stadium, fans stand up and sit down to produce a wave across the stadium. This type of wave where the material travels perp

puteri [66]

Correct option B

Transverse waves are those waves whose particles vibrate perpendicular to the direction of wave.

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3 0

3 years ago

Read 2 more answers

At some instant and location the electric field associated with an electromagnetic wave in vacuum has the strength 96.5 V/m. Fin

prisoha [69]

Answer:

B = 32.17 x 10^-8 Tesla

u = 8.24 x 10^-8 J/m^3

P/A = 24.72 W/m^2

Explanation:

E = 96.5 V/m

velocity of light, c = 3 x 10^8 m/s

Let B be the magnetic field.

The relation between the electric field strength and the magnetic field strength is given by

B = E / c = 96.5 / (3 x 10^8) = 32.17 x 10^-8 Tesla

Let u be the energy density.

$u = \frac{1}{2}\times \varepsilon _{0}E^{2}+\frac{1}{2\mu _{0}}B^{2}$

$u = \frac{1}{2}\times 8.854\times 10^{-12}\times 96.5\times 96.5+\frac{1}{2\times 4\times 3.14\times 10^{-7}}\times 32.17^{2}\times 10^{-16}$

u = 8.24 x 10^-8 J/m^3

Let Power flow per unit area is

P/A = u x c = 8.24 x 10^-8 x 3 x 10^8 = 24.72 W/m^2

7 0

3 years ago

Two balls are dropped from rest and allowed to fall. If one ball is allowed to fall for 1 s and the other for 3 s compare the di

kirill115 [55]

The second ball traveled a greater distance when compared to the first ball because the second ball spent more time in motion.

The given parameters;

time of fall of the first ball, t = 1 s
time of fall of the second ball, t = 3 s

The distance traveled by each ball is calculated using the second equation of motion as shown below.

The distance traveled by the first ball is calculated as follows;

$h = u_0t + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\h = (0.5\times 9.8\times 1^2)\\\\h = 4.9 \ m$

The distance traveled by the second ball is calculated as follows;

$h = \frac{1}{2} gt^2\\\\h = (0.5\times 9.8\times 3^2)\\\\h = 44.1\ m$

Thus, the second ball traveled a greater distance because it spent more time in motion.

Learn more here:brainly.com/question/5868480

3 0

2 years ago

When going from slower medium to a faster medium, light is bent _____.

Damm [24]

Answer:

When going from slower medium to a faster medium, light is bent _downwards_.

Explanation:

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8 0

3 years ago

Read 2 more answers

A car accelerates uniformly from rest to a final speed of 19 m/s in 10. seconds. How far does it travel during this period of ac

lions [1.4K]

Answer:

x = 95 [m]

Explanation:

To solve this problem we must use the following equation of kinematics.

$v_{f} =v_{o} +a*t$

where:

Vf = final velocity = 19 [m/s]

Vo = initial velocity = 0 (starts from the rest)

a = acceleration [m/s²]

t = time = 10 [s]

Now we can find the acceleration

19 = 0 *a*(10)

a = 1.9 [m/s]

With the second equation we can find the distance:

$v_{f} ^{2} =v_{o} ^{2} +(2*a*x)$

where:

x = distance [m]

(19)² = (0)² + (2*1.9*x)

3.8*x = 361

x = 95 [m]

7 0

3 years ago