Answer:
W = 30 J
Explanation:
given,
Work done = 10 J
Stretch of spring, x = 0.1 m
We know,
dW = F .dx
we know, F = k x


![W = k[\dfrac{x^2}{2}]_0^{0.1}](https://tex.z-dn.net/?f=W%20%3D%20k%5B%5Cdfrac%7Bx%5E2%7D%7B2%7D%5D_0%5E%7B0.1%7D)

k = 2000
now, calculating Work done by the spring when it stretched to 0.2 m from 0.1 m.

![W = 2000 [\dfrac{x^2}{2}]_{0.1}^{0.2} dx](https://tex.z-dn.net/?f=W%20%3D%202000%20%5B%5Cdfrac%7Bx%5E2%7D%7B2%7D%5D_%7B0.1%7D%5E%7B0.2%7D%20dx)
W = 1000 x 0.03
W = 30 J
Hence, work done is equal to 30 J.
Answer:

Explanation:
Follow the schematic in which point A is the warehouse and point D is the destination.
Now we observe the triangle constructed
:
here:


&

As we know that displacement is the shortest distance between two points.
<u>Using Pythagoras theorem:</u>



The diameter of a ball is 3.8 cm.
Because 400/3.8 = 105.26,
each dimension of 400 m can accommodate 105 balls.
Similarly, because 300/3.8 = 78.95,
each dimension of 300 m can accommodate 78 balls.
The total number of balls is 105*105*78 = 859,950
Answer: 859,950 balls