Question

A car accelerates uniformly from rest to a final speed of 19 m/s in 10. seconds. How far does it travel during this period of acceleration?

Answer 1

Answer:

x = 95 [m]

Explanation:

To solve this problem we must use the following equation of kinematics.

$v_{f} =v_{o} +a*t$

where:

Vf = final velocity = 19 [m/s]

Vo = initial velocity = 0 (starts from the rest)

a = acceleration [m/s²]

t = time = 10 [s]

Now we can find the acceleration

19 = 0 *a*(10)

a = 1.9 [m/s]

With the second equation we can find the distance:

$v_{f} ^{2} =v_{o} ^{2} +(2*a*x)$

where:

x = distance [m]

(19)² = (0)² + (2*1.9*x)

3.8*x = 361

x = 95 [m]