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Leviafan [203]
4 years ago
6

PLEASE HELP! What is the length of segment AB? A. ^13, B. ^85, C. 13, D. 14

Mathematics
1 answer:
Talja [164]4 years ago
7 0

Answer:

· Line segment A'B', whose endpoints are (4, -2) and (16, 14) is the image of AB after a dilation of 1/2 centered at the origin. What is the length of AB? (4) 40. You could either find the length and double it (the image is 1/2 the original) or you can double the x- and y-values and then find the length. Your choice.

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Read 2 more answers
Help please !! need it asap
NNADVOKAT [17]
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6 0
3 years ago
PLEASE HELP! 25 PTS!!
zubka84 [21]

Answer:

Solution given:

f(x)=\frac{x-16}{x^2+6x-40}

g(x)=\frac{1}{x+10}

now

f(x)+g(x)=\frac{x-16}{x^2+6x-40}+\frac{1}{x+10}....(1)

now

factoring x²+6x-40

we get

x²+10x-4x-40

x(x+10)-4(x+10)

(x+10)(x-4)

now substituting in equation 1 ,we get

f(x)+g(x)=\frac{x-16}{(x+10)(x-4)}+\frac{1}{x+10}

taking l.c.m

=\frac{(x-16)+(x-4)}{(x-10)(x-4)}

=now

opening bracket

\frac{x-16+x-4}{x²-10x-4x+40}

=\frac{2x-20}{x²+6x-40}

So

answer is :

B. \bold b\frac{2x-20}{x^2+6x-40}

6 0
3 years ago
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iragen [17]
6/ 3/4
6(4/3)
= 8

The answer is 8. 
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