Answer:
1/10
hope it helps!!!!
Answer:
-1, 2 and 4
Step-by-step explanation:
Answer:
He bought approximately 16 pigs.
Step-by-step explanation:
In order to find how many pigs the farmer had originally all you have to do is add three to amount of pigs he sold, since three of the died. In order to find how many he sold all you need to do is divide 109 by 8, since he made a profit of $8 per pig. 109 / 8 = 13.625, 13.625 + 3 = 16.625
The minimum value of a function is the place where the graph has a vertex at its lowest point.
There are two methods for determining the minimum value of a quadratic equation. Each of them can be useful in determining the minimum.
(1) By plotting graph
We can find the minimum value visually by graphing the equation and finding the minimum point on the graph. The y-value of the vertex of the graph will be the minimum.
(2) By solving equation
The second way to find the minimum value comes when we have the equation y = ax² + bx + c.
If our equation is in the form y = ax^2 + bx + c, you can find the minimum by using the equation min = c - b²/4a.
The first step is to determine whether your equation gives a maximum or minimum. This can be done by looking at the x² term.
If this term is positive, the vertex point will be a minimum; if it is negative, the vertex will be a maximum.
After determining that we actually will have a minimum point, use the equation to find it.
Where p is the distance the focus is above the vertex, the equation of a parabola with vertex (h, k) can be written as
... y = 1/(4p)·(x -h)² +k
The vertex is halfway between the focus and directrix. The focus of your parabola is on the y-axis at y=6, and the directrix of your parabola is at y=-6, so the vertex of your parabola is on the y-axis at y=0. That is, the vertex is
... (h, k) = (0, 0).
The distance p from the focus at y=6 to the vertex at y=0 is 6 units, so
... p = 6.
Filling these values into the equation gives
... y = 1/(4·6)·(x -0)² +0
... y = (1/24)x²
