The only way without a while loop and no method I can think of is use switch with every possible variation of the four digit binary which is 15.
Here is the starter code:
import java.util.Scanner;
public class MyClass {
public static void main(String args[]) {
Scanner sc = new Scanner(System.in);
int digit = sc.nextInt();
switch(digit) {
case 0000:
System.out.println("0");
break;
case 0001:
System.out.println("1");
break;
case 0010:
System.out.println("2");
break;
case 0011:
System.out.println("3");
break;
case 0100:
System.out.println("4");
break;
… (fill in other cases)
}
}
}
Use this link: https://www.electronics-tutorials.ws/binary/bin_3.html
There might be a better way, but without loops or methods this is all I got.
Answer:
To store decimal values
Explanation:
Analyzing the given options.
(a)
Decimal values are digits and are to be treated as such. So, storing them as strings mean that they are no longer decimal values.
(b), (c) & (d)
List of colors, words and values that can't be used for calculations are all string values.
Take a for instance.
List of colors: "Red", "Yellow", "Blue",...
Words, "I", "am", "a", "boy"
Values that can't be used for calculations are non numerical data and as such, some of them could be strings.
Hence:
Option (a) answers the question
Answer:
Option B is the correct option.
Explanation:
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Bachelor's degree would be next in line .. im taking the test as well im going with A.
