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Lapatulllka [165]
3 years ago
15

A catalog store has 6% of its orders returned for a refund. the owner predicts that a new candle will have 812 returns put of th

e 16,824 sold. Do you agree with this predictions?
Mathematics
1 answer:
saw5 [17]3 years ago
8 0
16824 x .06 = 1009.44

.06 is 6% in decimal form.

So no, they would have more if we are assuming the 6% is true.
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Since 2.5% as a decimal is .025, the equation to get this is:

(.025)(80000)

Once multiplied, these equal 2,000. Or in other words, the Smiths pay $2,000 in school taxes per year.
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I need help on number 4?
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The graph below shows the function f(x)=x-3/x2-2x-3. Which statement is true?
BARSIC [14]
1. Domain.

We have x^2-2x-3 in the denominator, so:

x^2-2x-3\neq0\\\\(x^2-2x+1)-4\neq0\\\\(x-1)^2-4\neq0\\\\(x-1)^2-2^2\neq0\qquad\qquad[\text{use }a^2-b^2=(a-b)(a+b)]\\\\(x-1-2)(x-1+2)\neq0\\\\
(x-3)(x+1)\neq0\\\\\boxed{x\neq3\qquad\wedge\qquad x\neq-1}

So there is a hole or an asymptote at x = 3 and x = -1 and we know, that answer B) is wrong.

2. Asymptotes:

f(x)=\dfrac{x-3}{x^2-2x-3}=\dfrac{x-3}{(x-3)(x+1)}=\boxed{\dfrac{1}{x+1}}

We have only one asymptote at x = -1 (and hole at x = 3), thus the correct answer is A)
6 0
3 years ago
Read 2 more answers
I have no idea how to do this, it is due in two days. Hopefully someone sees this before then.
elena-14-01-66 [18.8K]

Hello,

m\ \widehat{ABC}=x\\m\ \widehat{BAC}=2*x\\\\So:\\ x+2x=90^o\\x=30^o\\

cos(30^o)=\dfrac{\sqrt{3} }{2} \\

In the triangle ABC,

cos(30^o)=\frac{BC}{BA} \\\\BA=\dfrac{cos(30^o)}{BC} \\\\BA=\frac{\dfrac{\sqrt{3} }{2} }{24} =16*\sqrt{3} \\\\

sin(30^o)=\dfrac{1 }{2} =\dfrac{AC}{AB} \\\\AC=\dfrac{1}{2} *16\sqrt{3} =8\sqrt{3}

In the triangle ACB,

cos(30^o)=\dfrac{AC}{AL} \\\\AL=\dfrac{8\sqrt{3} *2}{\sqrt{3} } =16\\

6 0
3 years ago
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