72 is multiples of 3,9, and 12
This might help you..need more information
Answer:
Step-by-step explanation:
a). There are 8 points in the figure attached.
b). There are 9 lines in the given figure.
c). There are 5 planes in the figure attached.
d). Three collinear points are D,G and F.
e). Four co-planar points are G, F, H and C.
f). Intersection of planes ABC and ABE is the common line AB.
g). Intersection of planes BCH and DEF is the common line EF.
h). Intersection of AD and DF is a point D.
We have the following information:
first urn: 6 green balls and 3 red ones
total: 6 + 3 = 9
second urn: 3 green, 3 white and 3 red
total: 3 + 3 + 3 = 9
third urn: 6 green, 1 white and 2 red
total: 6 + 1 + 2 = 9
a) A green ball is more likely to be obtained, since there are more green balls than red balls, which makes the probability higher.
b) probability of drawing a green, red and white ball.
first urn:
green = 6/9 = 66.66%
red = 3/9 = 33.33%
white = 0/9 = 0%
second urn:
green = 3/9 = 33.33%
red = 3/9 = 33.33%
white = 3/9 = 33.33%
third urn:
green = 6/9 = 66.66%
red = 2/9 = 22.22%
white = 1/9 = 11.11%
c) it would be chosen where the probability of drawing green would be the highest, which means that it would be possible both in the first and in the third ballot box, the probability is equal 66.66%
d) without a green ball, the third ballot box would look like this:
5 green balls, 2 red balls and 1 white ball, with a total of 8.
The probability of drawing would be:
green = 5/8 = 62.5%
red = 2/8 = 25%
white = 1/8 = 12.5%
0.003 is 1/10 of 0.03.
Just multiply the 0.003 by 10 and you'll get the answer.
