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3 years ago

The sides of a octagon each have a length of 8x inches.write an expression for the Perimeter of the octagon in inches

Mathematics

1 answer:

miss Akunina [59]3 years ago

6 0

8(8x)

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What the answer to this equation X/8+4=5 ?

V125BC [204]

Answer:

The answer to this equation is 8

Step-by-step explanation:

$\frac{x}{8} +4=5\\$

First: Subtract

$8-4=4$

$5 > 4$ meaning that 5 is greater than 4.

You still need another number to make it equal than or greater than or equal to five.

$5-4=1$

Since 5 minus 4 does equal 1

You need somewhere to divide it from to get 1 so you can add up the 4 to it and get the answer to the equation.

Lastly: Divide

$\frac{8}{8} =1$

$1+4=5\\5=5\\4\neq 5$

Now, if you do 8/8 which equals 1, 1+4 = 5; Now everything is, equaled up!

So in conclusion...

$\frac{x}{8} +4=5\\x=8\\\frac{8}{8}=1\\1+4=5\\5\neq5$

3 0

3 years ago

Read 2 more answers

Wendy had 1/2 of her birthday cake left over, so she decided to take it to work.

Aloiza [94]

Answer:

1/12

Step-by-step explanation:

1/2 divided by 6

that way her and her 5 workers each get the same amount of cake

5 0

3 years ago

Read 2 more answers

in the figure below trianglePQM and triangleQRP are right triangles. the measure of lineQM is 6 and the measure of lineQP is 8.

Kipish [7]

Answer:

Option 4 is correct. The length of PR is 6.4 units.

Step-by-step explanation:

From the given figure it is noticed that the triangle PQR and triangle MQR.

Let the length of PR be x.

Pythagoras formula

$hypotenuse^2=base^2+perpendicular^2$

Use pythagoras formula for triangle PQM.

$PM^2=QM^2+PQ^2$

$PM^2=(6)^2+(8)^2$

$PM^2=36+64$

$PM^2=100$

$PM=10$

The value of PM is 10. The length of PR is x, so the length of MR is (10-x).

Use pythagoras formula for triangle PQR.

$PQ^2=QR^2+PR^2$

$(8)^2=QR^2+x^2$

$64-x^2=QR^2$ .....(1)

Use pythagoras formula for triangle MQR.

$MQ^2=QR^2+MR^2$

$(6)^2=QR^2+(10-x)^2$

$36=QR^2+x^2-20x+100$

$36-x^2+20x-100=QR^2$ .... (2)

From equation (1) and (2) we get

$36-x^2+20x-100=64-x^2$

$20x-64=64$

$20x=128$

$x=6.4$

Therefore length of PR is 6.4 units and option 4 is correct.

3 0

3 years ago

En el estante de un negocio hay 2 tipos de tarros de la misma mermelada y marca. El tarro más alto tiene el doble de altura que

Ipatiy [6.2K]

Answer:

tarro corto

Step-by-step explanation:

Aquí tenemos que comprar el frasco que tiene el menor costo por volumen.

$h_1$ = Altura del frasco corto

$h_2$ = La altura del frasco alto es el doble que el del frasco corto. = $2h_1$

$d_1$ = Diámetro del frasco corto

$d_2$ = El diámetro del frasco alto es la mitad del frasco corto = $\dfrac{1}{2}d_1$

El volumen de un cilindro es $\pi \dfrac{d^2}{4}h$

La razón de los volúmenes de los frascos es

$\dfrac{V_1}{V_2}=\dfrac{\pi\dfrac{d_1^2}{4}h_1}{\pi\dfrac{d_2^2}{4}h_2}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{d_2^2h_2}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{(\dfrac{1}{2}d_1)^22h_1}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{\dfrac{1}{4}d_1^22h_1}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{1}{\dfrac{1}{2}}\\\Rightarrow \dfrac{V_1}{V_2}=2\\\Rightarrow V_1=2V_2$

El costo del frasco corto por unidad de volumen es

$\dfrac{8000}{V_1}=\dfrac{8000}{2V_2}=\dfrac{4000}{V_2}$

El costo del frasco alto por unidad de volumen es

$\dfrac{4500}{V_2}=\dfrac{4500}{V_2}$

$\dfrac{4000}{V_2}$

Entonces, el costo del frasco corto por unidad de volumen es menor que el costo por unidad de volumen del frasco alto.

Por lo tanto, deberíamos tomar el frasco corto.

5 0

3 years ago

Tell me the Definition of each Word listed (math)

natita [175]

Constant: A value that doesn't change. Instead, it's a fixed value.

Variable: A symbol (usually a letter) standing in for an unknown numerical value in an equation.

Term: Either a single number or variable, or numbers and variables multiplied together. (Terms are separated by + or − signs, or sometimes by divide.)

Like Terms: Terms whose variables (and their exponents such as the 2 in x2) are the same. In other words, terms that are "like" each other.

Coefficient: A number used to multiply a variable.

3 0

3 years ago