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coldgirl [10]
3 years ago
15

Consider each of the following relationships. Which school shows the greatest rate of change between male and female students? ​

In school A, the ratio of male students to female students is 5:2. In school B, the relationship between the number of male students, y, and the number of female students, x, is given by the equation y = 2 x . In school C, the number of male and female students are as shown in the table.
female students 120
Male students 200
Mathematics
1 answer:
denis-greek [22]3 years ago
7 0

Answer:

The greatest rate of change is for <u>school A</u> as it has the greatest ratio of 2.5

Step-by-step explanation:

School A:

Ratio of male to female students, m_A=5:2=\frac{5}{2}=2.5

School B:

Male students are related to female students by equation:

y=2x

Where, x means number of female students and y means number of male students.

Therefore, the ratio of male to female students is, m_B=\frac{y}{x}=2

School C:

Ratio of male to female students is, m_C=\frac{\textrm{Number of male students}}{\textrm{Number of female students}}=\frac{200}{120}=1.67

Now, rate of change of male to female students is directly proportional to the ratio of the two.

Hence, the greater the ratio, the greater the rate of change.

So, the greatest rate of change is for school A as it has the greatest ratio of 2.5

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Answer:

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Step-by-step explanation:

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Now, you have a model for x in terms of y, which is what the question is asking for.

  x = log(y/4)/log(1.0256) . . . . . . . exact expression

When y=12, this is ...

  x = log(12/4)/log(1.0256) ≈ 43.46 . . . . weeks

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3 years ago
Complete the point slope equation of the line through (-5, 7) and (-4, 0).​
IgorLugansk [536]

For this case we have that by definition, the point-slope equation of a line is given by:

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b: It is the cut-off point with the y axis

We have two points:

(x_ {1}, y_ {1}): (- 5,7)\\(x_ {2}, y_ {2}): (- 4,0)

We found the slope:

m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} =  \frac {0-7} {- 4 - (- 5)} = \frac {-7} {-4 + 5} = \frac {-7} {1} = - 7

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3 years ago
Will mark brainliest! Answer quickly please.
inn [45]
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3 0
2 years ago
Ayuda por favor
sergeinik [125]

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

<h3>¿Cómo determinar la medida de un lado de un triángulo desconocido?</h3>

En este problema tenemos un sistema formado por dos triángulos <em>similares</em>, la semejanza entre los dos triángulos se debe a la colinealidad entre los segmentos de línea AP' (triángulo <em>pequeño</em>) y AP'' (triángulo <em>grande</em>), así como de los lados AM y AB, así como los lados AN y AC, así como los <em>mismos</em> ángulos en la <em>misma</em> distribución. (Semejanza Lado - Ángulo - Lado)

En consecuencia, obtenemos las siguientes proporciones:

AP'/AP'' = MN/BC = 1/2     (1)

Finalmente, la proporción entre el triángulo AMN y el cuadrilátero BMNC es:

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)}{\frac{1}{2}\cdot (2\cdot a) \cdot  h - \frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)} = \frac{\frac{1}{4}\cdot a\cdot h }{a\cdot h - \frac{1}{4}\cdot a \cdot h }

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{4} }{\frac{3}{4} } = \frac{1}{3}

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

Para aprender sobre triángulos semejantes: brainly.com/question/21730013

#SPJ1

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