Need help with this!!!!!!!!

Mathematics

1 answer:

zzz [600]4 years ago

4 0

The linear combination method is the same as the elimination method. Let's multiply the second equation by -2 so the x terms cancel each other out. When we do that we get a system of $2x-3y=13$ and $-2x-4y=8$ . The x-terms cancel each other out giving us $-7y=21$ and y = -3. Now sub -3 into one of the equations to solve for x. x+2(-3)=-4, and x - 6 = -4. x = 2. So the solution for our system is (2, -3)

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Can someone explain this step by step? I'm very confused on how to solve it. Thanks!

Rashid [163]

Answer:

x = -8

Step-by-step explanation:

I will show each step algebraically. If you need further explanation, feel free to ask questions :)

$\frac{x}{2} +7=3\\$ Rewrite

$\frac{x}{2} =-4$ Subtract 7

$x =-8$ Multiply by reciprocal (2/1)

I hope this helps!

3 0

3 years ago

Read 2 more answers

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qaws [65]

Answer:My answer is Temp-pH I

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3 years ago

Please show your work and explain it.

Maru [420]

Answer:

$f(x)=\dfrac{x+2}{2(x-2)}$

Step-by-step explanation:

Remember when you divide fractions, you need to get the reciprocal of the divisor and multiply. So your first simplification would be:

$\dfrac{x^2+4x+4}{x^2-6x+8}\div\dfrac{6x+12}{3x-12}\\\\=\dfrac{x^2+4x+4}{x^2-6x+8}\times\dfrac{3x-12}{6x+12}\\\\=\dfrac{(x^2+4x+4)(3x-12)}{(x^2-6x+8)(6x+12)}$