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n200080 [17]
3 years ago
5

Find the x value x^2 - 3x + 2 = 0

Mathematics
2 answers:
Damm [24]3 years ago
4 0

Answer:

x=2 and x=1

Step-by-step explanation:

x^2 - 3x + 2 = 0

(x-2)(x-1) = 0

(x-2)=0

x=2

(x-1) = 0

x=1

so values are x=2 and x=1

Hope this helps ...Pls Mark me as Brainliest!!

ladessa [460]3 years ago
3 0

Answer:

2 and 1

Step-by-step explanation:

x^2 - 3x + 2 = 0

(x-2)(x-1) = 0

the x can be 2 and 1

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Hi, can you help to find (all the roots/zeros), please!!!
OLga [1]

Solution

Given the quadratic equation

x^2-2x-38=0

we need to find the zeros of the equation

To do that, we use the completing the square method

Step 1. Add 38 to both sides

\begin{gathered} \Rightarrow x^2-2x-38+38=38 \\  \\ \Rightarrow x^2-2x=38 \end{gathered}

Step 2: add the square of half of the coefficient of x to both sides

That is;

\begin{gathered} \Rightarrow x^2-2x+(\frac{1}{2}\cdot(-2))^2=38+(\frac{1}{2}\cdot(-2))^2 \\  \\ \Rightarrow x^2-2x+1=38+1 \\  \\ \Rightarrow x^2-2x+1=39 \\  \\ \Rightarrow(x-1)^2=39 \end{gathered}

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4 0
1 year ago
X=3y-4<br> 2x-y=7<br> use substitution method. pls explain :)
Nesterboy [21]

Answer:

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