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pentagon [3]
2 years ago
9

How are force and motion related

Physics
1 answer:
sp2606 [1]2 years ago
5 0
Force is used to put things in motion you can’t have motion without force!
Even if it just pushing a piece of paper you still use force to put the paper in motion!
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This diagram shows how a certain type of precipitation is formed. Water drops are caught in up-drafts and down-drafts, over and
Svet_ta [14]

It would be B. Hail.

5 0
3 years ago
A clay vase on a potter's wheel experiences an angular acceleration of 5.69 rad/s2 due to the application of a 16.0-n m net torq
Digiron [165]
The equivalent of the Newton's second law for rotational motions is:
\tau = I \alpha
where
\tau is the net torque acting on the object
I is its moment of inertia
\alpha is the angular acceleration of the object.

Re-arranging the formula, we get
I= \frac{\tau}{\alpha}
and since we know the net torque acting on the (vase+potter's wheel) system, \tau=16.0 Nm, and its angular acceleration, \alpha = 5.69 rad/s^2, we can calculate the moment of inertia of the system:
I= \frac{\tau}{\alpha}= \frac{16.0 Nm}{5.69 rad/s^2} =2.81 kg m^2
8 0
3 years ago
Which of the following is the tendency of an object to maintain its state of
densk [106]

Answer:

O inertia

Explanation:

The tendency of a body to maintain its state of motion is inertia.

Inertia is the tendency of a body to remain at rest or in constant motion.

  • According to newtons first law of motion "a body will remain in its state of rest or constant motion unless acted upon by an external force".
  • The tendency of the body to remain in a state of rest or of constant motion is the inertia.
  • Such a body will not want to accelerate or change motion.
7 0
3 years ago
A ball is tossed with a velocity of 10 m/s directed vertically upward from a window located 20 m above the ground. Determine the
marusya05 [52]

Answer:

Explanation:

Given

Initial velocity of ball u=10\ m/s

height of window h=20\ m

Using Equation of motion

y=ut+\frac{1}{2}at^2

where u=initial velocity

t=time

a=acceleration

As ball is already is at a height of 20 m so

Y=ut+\frac{1}{2}at^2+20

Y=10\times t+0.5\times (-9.8)t^2+20

Y=-4.9t^2+10t+20

(b)highest point is obtained at v=0

v^2-u^2=2as

where

v=final velocity

u=initial velocity

a=acceleration

s=displacement

(0)-10^2=2\times (-9.8)\times s

s=\frac{100}{19.6}

s=5.102\ m

Highest Point will be s+20=25.102\ m

(c)Time taken when the ball hit the ground i.e. at Y=0

-4.9t^2+10t+20=0

t=3.28\ s

impact velocity v=\sqrt{2\times 9.8\times 25.102}

v=22.181\ m/s

7 0
3 years ago
Youssef and Sophia are driving in two different cars and not paying attention to their surroundings. Youssef approaches an inter
Reptile [31]

Answer:

I think  E--

Explanation:

3 0
2 years ago
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