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Lubov Fominskaja [6]

3 years ago

7

prc-2) A soccer ball accelerates from rest and rolls 6.5m down a hill for 3.1 seconds. It is then stopped by a tree. Find the fi

nal velocity.

1 answer:

anastassius [24]3 years ago

7 0

Answer:

15?6 and 17 plus 18 equals e b d f g so correct

Explanation:

yws you're welcome and thank for your help with this and I will be there is it ok if I get a and I can

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Neko [114]

Answer:

8000 - 5000 =3000

Explanation:

8 0

3 years ago

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a diver of mass 101 kg jumps upward off a diving board into water. Diving board is 6m above water. Diver has a speed of 1.2m/s.

8090 [49]

When the diver reaches maximum height, the upward velocity will be zero.

We shall use the formula
v^2 = u^2 - 2gh
where
v = 0 (velocity at maximum height)
u = 1.2 m/s, intial upward velocity
g = -9.8 m/s^2, gravitational acceleration (downward)
h = maximum height attained above the diving board.

Therefore
0 = 1.2^2 - 2*9.8*h
h = 1.2^2/(2*9.8) = 0.0735 m

Answer: 0.074 m (nearest thousandth)

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3 years ago

What is the result of (305.120 + 267.443) x 0.50? How many answers can be written based on the principle of significant digits?

NNADVOKAT [17]

Answer:

The answer is 286.2815.

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2 years ago

A positively charged wire with uniform charge density +λ lies along the x-axis and a negatively charged wire with uniform charge

Kisachek [45]

Answer:

$\vec{E} = \frac{\lambda}{2\pi\epsilon_0}[\frac{1}{y}(\^y) - \frac{1}{x}(\^x)]$

Explanation:

The electric field created by an infinitely long wire can be found by Gauss' Law.

$\int \vec{E}d\vec{a} = \frac{Q_{enc}}{\epsilon_0}\\E2\pi r h = \frac{\lambda h}{\epsilon_0}\\\vec{E} = \frac{\lambda}{2\pi\epsilon_0 r} \^r$

For the electric field at point (x,y), the superposition of electric fields created by both lines should be calculated. The distance 'r' for the first wire is equal to 'y', and equal to 'x' for the second wire.

$\vec{E} = \vec{E}_1 + \vec{E}_2 = \frac{\lambda}{2\pi\epsilon_0 y}(\^y) + \frac{-\lambda}{2\pi\epsilon_0 x}(\^x)\\\vec{E} = \frac{\lambda}{2\pi\epsilon_0 y}(\^y) - \frac{\lambda}{2\pi\epsilon_0 x}(\^x)\\\vec{E} = \frac{\lambda}{2\pi\epsilon_0}[\frac{1}{y}(\^y) - \frac{1}{x}(\^x)]$

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3 years ago

Explain the main function of components of blood.

olga55 [171]

responsible for carrying oxygen and carbon dioxide...

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2 years ago