This is kinetic energy to heat energy
Answer
Explanation:
Convert the time to seconds = 0.6 × 60 × 60
= 2160seconds
Velocity = distance ÷ time
Velocity = 500 ÷ 2160
Velocity = 0.23meters per seconds(m/s)
Acceleration = Velocity ÷ time
Acceleration = 0.23 ÷ 2160
Acceleration = 0.000106meters per seconds ²(m/s²)
Answer:

Explanation:
First we need to find the capacitance of the capacitor.
The capacitance is given by:

Where
is the air permittivity, which is approximately 8.85 * 10^(-12)
The radius is 12/2 = 6 mm = 0.006 m, so the area of the capacitor is:

So the capacitance is:


The time constant of a rc-circuit is given by:

So we have that:

Answer:
3.6 s.
Explanation:
Impulse: This can be defined as the product of force and time. The S.I unit of impulse is N.s.
From newton's second law of motion,
The expression for impulse is given as,
I = Ft = m(u-v) ................. Equation 1
make t the subject of the equation
t = m(v-u)/F................... Equation 2
Where I = impulse, v = final velocity, u = initial velocity, m = mass of the ball, F = force, t = time
Given: m = 3 kg, F = 5 N, u = 9 m/s, v = 3 m/s
Substitute into equation 2
t = 3(9-3)/5
t = 3(6)/5
t = 3.6 s.
Answer:
q = 8.61 10⁻¹¹ m
charge does not depend on the distance between the two ships.
it is a very small charge value so it should be easy to create in each one
Explanation:
In this exercise we have two forces in balance: the electric force and the gravitational force
F_e -F_g = 0
F_e = F_g
Since the gravitational force is always attractive, the electric force must be repulsive, which implies that the electric charge in the two ships must be of the same sign.
Let's write Coulomb's law and gravitational attraction
In the exercise, indicate that the two ships are identical, therefore the masses of the ships are the same and we will place the same charge on each one.
k q² = G m²
q =
m
we substitute
q =
m
q =
m
q = 0.861 10⁻¹⁰ m
q = 8.61 10⁻¹¹ m
This amount of charge does not depend on the distance between the two ships.
It is also proportional to the mass of the ships with the proportionality factor found.
Suppose the ships have a mass of m = 1000 kg, let's find the cargo
q = 8.61 10⁻¹¹ 10³
q = 8.61 10⁻⁸ C
this is a very small charge value so it should be easy to create in each one