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3 years ago

What can cause a magnetic domain to form?

Physics

2 answers:

puteri [66]3 years ago

7 0

Answer:

D. magnetic fields of atoms being aligned with each other

Explanation:

Morgarella [4.7K]3 years ago

4 0

Answer:

Explanation:

Magnetic domains are always present in ferromagnetic materials due to the way the atoms bond to form the material. However, when a ferromagnetic material is in the unmagnetized condition, the magnetic domains are randomly oriented so that the magnetic field strength in the piece of material is zero.

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While entering a freeway, a car accelerates from rest at a rate of 2.40 m/s2 for 12.0 s. (a) Draw a sketch of the situation. (b)

ArbitrLikvidat [17]

Answer:

a) See attached picture, b) We know the initial velocity = 0, initial position=0, time=12.0s, acceleration= $2.40m/s^{2}$ , c) the car travels 172.8m in those 12 seconds, d) The car's final velocity is 28.8m/s

Explanation:

a) In order to draw a sketch of the situation, I must include the data I know, the data I would like to know and a drawing of the car including the direction of the movement and its acceleration, just like in the attached picture.

b) From the information given by the problem I know:

initial velocity =0

acceleration = $2.40m/s^{2}$

time = 12.0 s

initial position = 0

unknown:

displacement.

in order to choose the appropriate equation, I must take the knowns and the unknown and look for a formula I can use to solve for the unknown. I know the initial velocity, initial position, time, acceleration and I want to find out the displacement. The formula that contains all this data is the following:

$x=x_{0}+V_{x0}t+\frac{1}{2}a_{x}t^{2}$

Once I got the equation I need to find the displacement, I can plug the known values in, like this:

$x=0+0(12s)+\frac{1}{2}(2.40\frac{m}{s^{2}} )(12s)^{2}$

after cancelling the pertinent units, I get that my answer will be given in meters. So I get:

$x=\frac{1}{2} (2.40\frac{m}{s^{2}} )(12s)^{2}$

which solves to:

$x=172.8m$

So the displacement of the car in 12 seconds is 172.8m, which makes sense taking into account that it will be accelerating for 12 seconds and each second its velocity will increase by 2.4m/s.

d) So, like the previous part of the problem, I know the initial position of the car, the time it travels, the initial velocity and its acceleration. Now I also know what its final position is, so we have more than enough information to find this answer out.

I need to find the final velocity, so I need to use an equation that will use some or all of the known data and the unknown. In order to solve this problem, I can use the following equation:

$a=\frac{V_{f}-V_{0} }{t}$

Next, since I need to find the final velocity, I can solve the equation just for that, I can start by multiplying both sides by t so I get:

$at=V_{f}-V_{0}$

and finally I can add $V_{0}$ to both sides so I get:

$V_{f}=at+V_{0}$

and now I can proceed and substitute the known values:

$V_{f}=at+V_{0}$

$V_{f}=(2.40\frac{m}{s^{2}}} (12s)+0$

which solves to:

$V_{f}=28.8m/s$

8 0

3 years ago

Read 2 more answers

the red arrow shows the direction that wind from the south pole would travel if earth were not spinning. the wind's destination

MissTica

Answer: It should be A or the very left red circle that you can click on

Explanation: Because when the wind is moving downward and the earth is spinning the spot the wind ends up will never be directly down from where it was to begin with

6 0

3 years ago

Suppose an electrical wire is replaced with one having every linear dimension doubled (i.e. the length and radius have twice the

saul85 [17]

Answer:

The wire now has less (the half resistance) than before.

Explanation:

The resistance in a wire is calculated as:

$R=\alpha \frac{l}{s}$

Were:

R is resistance

$\alpha$ is the resistance coefficient

l is the length of the material

s is the area of the transversal wire, in the case of wire will be circular area ( $s=\pi r^{2}$ ).

So if the lenght and radius are doubled, the equation goes as follows:

$R=\alpha \frac{l}{\pi r^{2} } =\alpha \frac{2l}{\pi {(2r)}^{2} } =\alpha \frac{2l}{\pi 4 {r}^{2} }=\frac{1}{2} \alpha \frac{l}{\pi r^{2} }$

So finally because the circular area is a square function, the resulting equation is half of the one before.

7 0

3 years ago

PLEASE HELP!!! GIVING BRAINLIEST!! ill also answer questions that you have posted if you answer this correctly!!!! (60pts)

Alona [7]

Answer:

Weight

Explanation:

"An object will float if the buoyancy force exerted on it by the fluid balances its weight, i.e. if FB=mg F B = mg . But the Archimedes principle states that the buoyant force is the weight of the fluid displaced. So, for a floating object on a liquid, the weight of the displaced liquid is the weight of the object."

Hope this helps! :)

4 0

2 years ago

A 1-kg book is at rest on a desk. Determine the force the desk exerts on the book<br>

Katena32 [7]

<h3>Answer:</h3>

$\displaystyle F_n = 9.8 \ N$

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Physics</u>

<u>Forces</u>

SI Unit: Newtons N

Free Body Diagrams

Gravitational Force: $\displaystyle F_g = mg$

m is mass (in kg)
g is Earth's gravity (<em>9.8 m/s²</em>)

Normal Force: $\displaystyle F_n$

Newton's Law of Motions

Newton's 1st Law of Motion: An object at rest remains at rest and an object in motion stays in motion
Newton's 2nd Law of Motion: F = ma (Force is equal to [constant] mass times acceleration)
Newton's 3rd Law of Motion: For every action, there is an equal and opposite reaction

<h3>Explanation:</h3>

<u>Step 1: Define</u>

1 kg book at <em>rest</em>

<em>See Attachment</em>

<em>Draw a free body diagram to label the forces acting upon the book. We see that we would have gravitational force from Earth pointing downwards and normal force from the surface of the desk pointing upwards.</em>

<em>Since the book is not moving, we know that ∑F = 0 (sum of forces equal to 0).</em>

<u>Step 4: Find Normal Force</u>

Define Forces [Newton's Law of Motions]: $\displaystyle \sum F = 0$
[Newton's Law of Motions] Substitute in forces: $\displaystyle F_g - F_n = 0$
[Newton's Law of Motions] [Addition Property of Equality] Isolate $\displaystyle F_n$ : $\displaystyle F_g = F_n$
[Newton's Law of Motions] Substitute in $\displaystyle F_g$ : $\displaystyle mg = F_n$
[Newton's Law of Motions] Rewrite: $\displaystyle F_n = mg$
[Newton's Law of Motions] Substitute in variables: $\displaystyle F_n = (1 \ kg)(9.8 \ \frac{m}{s^2})$
[Newton's Law of Motions] Multiply: $\displaystyle F_n = 9.8 \ N$

7 0

2 years ago