Answer:
P = 10 kPa
Explanation:
Given that,
The mass of a small table, m = 4 kg
The area of each leg = 0.001 m²
We need to find the pressure exerted by the table on the floor. Pressure is equal to the force per unit area. So
So, the required pressure is 10 kPa.
Answer:
(A) 2.4 N-m
(B)
(C) 315.426 rad/sec
(D) 1741.13 J
(E) 725.481 rad
Explanation:
We have given mass of the disk m = 4.9 kg
Radius r = 0.12 m, that is distance = 0.12 m
Force F = 20 N
(a) Torque is equal to product of force and distance
So torque , here F is force and r is distance
So
(B) Moment of inertia is equal to
So
Torque is equal to
So angular acceleration
(C) As the disk starts from rest
So initial angular speed
Time t = 4.6 sec
From first equation of motion we know that
So
(D) Kinetic energy is equal to
(E) From second equation of motion