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Korvikt [17]
3 years ago
8

Lila is a track and field athlete. She must complete four laps around a circular track. The track itself is a 400 meter track an

d it took her 6 minutes total to complete. Which best describes her speed and velocity? A. Her speed is 4.4 m/s, and her velocity is 0 m/s B. Her speed is 1.1 m/s, and her velocity is 0 m/s C.Her speed is 0 m/s, and her velocity is 2400 m/s D. Her speed is 4.4 m/s, and her velocity is 4.4 m/s
Physics
1 answer:
Aleonysh [2.5K]3 years ago
6 0

Answer:

Her speed is 1.1 m/s, and her velocity is 0 m/s

Explanation:

Speed = Distance covered/Time

Given

Distance = 400m

Time = 6minutes = 6*60 = 360 secs

Substitute the given parameter into the formula;

Speed = 400/360

Speed = 1.1m/s

Since the track is a circular track, the displacement will be zero. She is only moving in a circular path (no direction)

Velocity = Displacement/Time

Velocity = 0/3600

Velocity = 0m/s

Hence her speed is 1.1 m/s, and her velocity is 0 m/s

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4 years ago
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Electrical energy in motion is what type of energy ?
Aleonysh [2.5K]

Answer:

kinetic energy

Explanation:

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A car has a distance between axles of 6.2 m and a center of mass located 2.2 m from the front axle. What is the
NARA [144]

Answer:

The correct option is  C

Explanation:

From the question we are told that

    The distance between axles of the car  is  d_a  =  6.2

     The position of the car's center of mass is  D  = 2.2 \ m  \ in \ front \  of  \  the \  axel

Now  we can evaluate the distance of the center of mass to the rear axle as follows

        k  =  d_a  -  D

substituting values

      k  =  6.2 -  2.2

      k  = 4 \ m

assuming the car is   at equilibrium,  taking moment about the center of mass

          W_{front \  axle} *  D  -  W_{rear \  axle} *  k  = 0

=>        W_{front \  axle} *  D     =  W_{rear \  axle} *  k

=>       \frac{W_{front \  axle}}{W_{rear \  axle} }       =    \frac{k}{D}

substituting values

             \frac{W_{front \  axle}}{W_{rear \  axle} }       =    \frac{4}{2.2}

           \frac{W_{front \  axle}}{W_{rear \  axle} }       =    1.81       Note [W_{front \  axle} is the front axle weight  and  

                                                      W_{rear \  axle} is the rear axle weight  ]

6 0
3 years ago
What mass of ice (in g) can be melted if 27.2 kJ of thermal energy are added at the freezing point? Use molar mass = 18.02 g/mol
san4es73 [151]

Answer : The mass of ice melted can be, 3.98 grams.

Explanation :

First we have to calculate the moles of ice.

Q=\frac{\Delta H}{n}

where,

Q = energy absorbed = 27.2 kJ

\Delta H = enthalpy of fusion of ice = 6.01 kJ/mol

n = moles = ?

Now put all the given values in the above expression, we get:

27.2kJ=\frac{6.01kJ/mol}{n}

n=0.221mol

Now we have to calculate the mass of ice.

\text{Mass of ice}=\text{Moles of ice}\times \text{Molar mass of ice}

Molar mass of ice = 18.02 g/mol

\text{Mass of ice}=0.221mol\times 18.02g/mol=3.98g

Thus, the mass of ice melted can be, 3.98 grams.

3 0
4 years ago
A man standing on a bus remains still when the bus is at rest. When the bus moves forward and then slows down the man continues
vovikov84 [41]

When the bus starts moving forward, the man remains at rest,
causing him to lean back.

When the bus slows down, the man continues to move forward,
and appears to lean forward.

Both events are examples of the effect of inertia.

6 0
4 years ago
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