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Karolina [17]
3 years ago
8

These are a musician favorite vegetable

Physics
2 answers:
Yanka [14]3 years ago
8 0
Beans.
As in the silly song "Beans, Beans, the magical fruit. The more you eat, the more you toot" lol
kicyunya [14]3 years ago
5 0
It is definitely an apple. I would know because i am a musician
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Neutron is commonly used to initiate a fission chain reaction.
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A child looks at his reflection in a spherical Christmas tree ornament 8.0 cm in diameter in season that the image of his face i
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From the information given,

diameter of ornament = 8

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Recall,

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magnification = image d

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2 years ago
If you were to apply a force of 15N to a medicine ball with a mass of 5kg, what would its acceleration be
yaroslaw [1]

Given that

Force (F) = 15 N ,

mass (m) = 5 Kg ,

acceleartion = ?

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                      F = m. a

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4 0
4 years ago
The direction of the magnetic field produced by an electric current will change when the direction of the ______changes.
Vinvika [58]

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5 0
3 years ago
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If the specific surface energy for magnesium oxide is 1.0 J/m2 and its modulus of elasticity is (225 GPa), compute the critical
alexdok [17]

Answer:

The critical stress required for the propagation of an initial crack              \sigma_{c} =  21.84 M pa

Explanation:

Given data

Modulus of elasticity E = 225 × 10^{9} \frac{N}{m^{2} }

Specific surface energy for magnesium oxide is \gamma_{s} = 1 \frac{J}{m^{2} }

Crack length (a) = 0.3 mm = 0.0003 m

Critical stress is given by \sigma_{c}^{2} } = \frac{2 E \gamma}{\pi a} -------- (1)

⇒ 2 E \gamma_{s} = 2 × 225 × 10^{9} × 1 = 450 × 10^{9}

⇒ \pi a = 3.14 × 0.0003 = 0.000942  

⇒ Put these values in equation 1 we get

⇒ \sigma_{c}^{2} } = \frac{450  }{0.000942} 10^{9}

⇒ \sigma_{c}^{2} } = 4.77 × 10^{14}

⇒ \sigma_{c} = 2.184 × 10^{7} \frac{N}{m^{2} }

⇒ \sigma_{c} =  21.84 \frac{N}{mm^{2} }

⇒ \sigma_{c} =  21.84 M pa

This is the critical stress required for the propagation of an initial crack.

4 0
3 years ago
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