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Gnoma [55]
2 years ago
11

How many electrons pass a given point in the circuit in 3 min? The fundamental charge is 1.602 × 10−19 C. amps: 0.415 , volts: 1

7 , ohms: 41
Physics
1 answer:
morpeh [17]2 years ago
4 0

The no of electron passing through the circuit is current by time. The no of electron passing are  46.63 x 10¹⁹ electrons.

<h3>What is charge?</h3>

The charge is the physical quantity which attracts or repels another object when comes into its field.

The time 3 min has 3 x 60 =180 seconds.

Total Charge Q = current I x time t

Q = 0.415 x 180

Q =74.7 coulombs

The no of electrons is the ratio of total charge divided by the fundamental charge.

n = 74.7/  1.602 × 10⁻¹⁹

n= 46.63 x 10¹⁹ electrons

Thus, electrons pass a given point in the circuit in 3 min are 46.63 x 10¹⁹ .

Learn more about charge.

brainly.com/question/11944606

#SPJ1

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The system is released from rest at θ = 0° when a constant couple moment M = 100 N.m is applied. If the mass of the cable and li
Fantom [35]

For a system released from rest at θ = 0° when a constant couple moment M = 100 N.m is applied,  the speed of the 10-kg block is mathematically given as

V=4.33m/s

<h3>What is the speed of the 10-kg block?</h3>

Generally, the equation for the workdone  is mathematically given as

W=T tehta<dtheta

W=100(90*\pi/180)

W=1.5707*100

W=1.57Nm

The change in potential energy across the pulley

dP=mgh

dp=10*9.81*111.8

dp=10.97J

For the thrid position, potential energy is

dP=mg(0.3)

dP=17.658J

dP'=17.658J-13.125

dP'=-4.532J

For 2nd position dP=0

The change in Kinectic energy across the pulley\

dK.E=0.5mv^2

For 1st

dk.E=0.5m(10)^2

2nd

dK.E=0.5Iw^2

dK.E=0.5(7.5*10^-3)(v^2/0.05)^2

3rd

2nd=3rd

In conclusion,

157.07=dKE+dP.E

157.07=5v^2+ (7.5*10^-3)(v^2/0.05)^2+10.97-4.53

V=4.33m/s

Read more about Kinetic energy

brainly.com/question/999862

4 0
2 years ago
Explain how a thumbtack is designed so that you do not have to use a lot of force to push it through paper or the surface of a b
Brums [2.3K]
Thumbtacks have a flat top which gives you a bigger area to push on, and the end is tapered and sharp to make it easier to push it into a wall, etc.
8 0
3 years ago
Aisha is sitting on frictionless ice and holding two heavy ski boots. Aisha weighs 637 N, and each boot has a mass of 4.50 kg. A
Studentka2010 [4]

Answer:

-0.73 m/s

Explanation:

We can solve this problem by using the law of conservation of momentum.

In fact, in absence of external forces (the ice is frictionless, so no friction), the total momentum of Aisha + two boots is conserved.

At the beginning, their total momentum is zero, since they are at rest:

p_i = 0 (1)

After, their total momentum is:

p_f = Mv + 2mv' (2)

where:

M is Aisha's mass

v is Aisha's velocity relative to the ground

m = 4.50 kg is the mass of each boot

v' is the boot's velocity relative to the ground

We can find:

M=\frac{W}{g}=\frac{637 N}{9.8 N/kg}=65 kg is Aisha's mass (where W = 637 N was her weight)

v' can be rewritten as:

v'=v+6

because 6 m/s is the velocity of the boots relative to her, while v' is their velocity relative to the ground.

Substituting and combining (1) and (2) we find:

0=Mv+2m(v+6)\\0=Mv+2mv+12m\\v=\frac{-12m}{M+2m}=\frac{-12(4.50)}{65+2(4.50)}=-0.73 m/s

and the negative sign indicates that the direction is opposite to that of the boots.

8 0
3 years ago
Where do light bulbs get their energy from?(1 point)
N76 [4]

<u>for instance, steel has a higher thermal conductivity than plastic. Hence, the steel plate gives away heat to the ice block faster than a plastic block does. As a result, ice melts faster on a steel plate than on a plastic one. Faster an object draws heat, the colder it feels.</u>

8 0
3 years ago
Read 2 more answers
We have a toy gun with a spring constant of 50 N/m. The spring is compressed by 0.2 m. If you neglect friction and the mass of t
Arisa [49]

Answer:

31.6\:\mathrm{m/s}

Explanation:

The elastic potential energy of a spring is given by Us=\frac{1}{2}kx^2, where k is the spring constant of the spring and x is displacement from point of equilibrium.

When released, this potential energy will be converted into kinetic energy. Kinetic energy is given by KE=\frac{1}{2}mv^2, where m is the mass of the object and v is the object's velocity.

Thus, we have:

Us=KE,\\\frac{1}{2}kx^2=\frac{1}{2}mv^2

Substituting given values, we get:

\frac{1}{2}\cdot 50\cdot 0.2^2=\frac{1}{2}\cdot 0.002\cdot v^2,\\v^2=\frac{50\cdot 0.2^2}{0.002},\\v^2=1000,\\v\approx \boxed{31.6\:\mathrm{m/s}}

4 0
3 years ago
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