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Kay [80]
2 years ago
7

How does velocity describe an objects motion?

Physics
1 answer:
rjkz [21]2 years ago
5 0

Answer:

Velocity is how fast and in what direction it moves.

Explanation:

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Reacting molecules must hit each other with sufficient energy in order to form products,what theory is it
7nadin3 [17]
It is called Arrhenius collision theory.
4 0
3 years ago
An insulated Thermos contains 140 cm3 of hot coffee at 85.0°C. You put in a 15.0 g ice cube at its melting point to cool the cof
Pavel [41]

Answer:

T = 69^o C

Explanation:

Here at thermal equilibrium we can say that thermal energy given by Hot coffee is equal to the thermal energy absorbed by ice cubes

So here we have

Q_{ice} = Q_{coffee}

now since ice cubes are added into coffee when it is at melting temperature

So here we can say that final temperature of coffee is T degree C

Now we have

m_1L + m_1c_1\Delta T_1 = m_2c_2\Delta T_2

here we have

m_1 = 15 gram

L = 333 kJ/kg = 333 J/g[/tex]

c_1 = c_2 = 4186 J/kg C = 4.186 J/g C

\Delta T_1 = T - 0

\Delta T_2 = 85 - T

now we have

15(333) + 15(4.186)(T - 0) = 140(4.186)(85 - T)

4995 + 62.79T = 49813.4 - 586.04T

648.83 T = 44818.4

T = 69^o C

6 0
3 years ago
I need help with an assignment a need help can someone help me SCIENCE.
Murljashka [212]

Answer:

ok whats the question?

Explanation:

5 0
3 years ago
A falling skydiver has a mass of 105 kg. What is the magnitude of the skydiver's acceleration when the upward force of air resis
LenKa [72]
F-free = m*g - F_air = m*a

F_air = 1.2 * m

a= (105 kg * 9.8 m.s^2 - 5*105) / 105 kg

a = 9.3 m/s

Hope this helps
7 0
3 years ago
La ecuación de la posición de una esferita está dada por: r(t)=(2.Cos(πt) i-3.Sen(πt) j) (m) ¿Cuál es la velocidad de la esferit
katovenus [111]

Answer:

v = (-4.44 i^ + 6.66 j^ )  m/s, a_average =( 0 i^ -2π j^) m/s²

Explanation:

The expression left corresponds to an oscillatory movement (MAS), the speed is defined by

         v = dr / dt

the function of position

         r = 2 cos πt  i^  + 3 sin πt  j^

let us note that it is a movement in two dimensions

let's perform the derivative

          v = -2π sin πt  i^  + 3π cos πt  j^

we evaluate this expression for t = 0.25 s, remember that the angle is in radians

          v = -2π sin (π 0.25) i^ + 3π cos (π 0.25) j^

           v = (-4.44 i^ + 6.66 j^ )  m/s

To calculate the mean acceleration we use the expression

           a = (v_{f} - v_{o}) / Δt

 

indicates that the time is the first 3 s

       

we look for the initial velocity t = 0 s

           v₀ = 0 i ^ + 3π j ^

         

we look for the fine velocity, t = 3 s

          v_f = - 2π sin (π 3) + 3π cos (π 3) j ^

          v_f = 0 i ^ - 3π j ^

we calculate the average acceleration

            Δt = (3 -0) = 3 s

           a_average = (0-0) / 3 i ^ + (-3π - 3π) / 3

           a_average = (0 i ^ -2π j ^ ) m/s²

6 0
3 years ago
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