A:b = 4:5
b:c=3:2
b was 5 then it was 3, so you have to find the common multiple which is 15.
you’d have to times the 4 (a) by 3 since that 5x3 is 15
you’d have to times the 2 (c) by 5 since 5x3 is 15 again.
therefore the answer would be
a:b:c
12:15:10
I hope this makes sense it was kinda hard to explain sorry :)
A composite number is a number with more than 2 factors and 16, 18, 20, and 21 are composite.
Answer:
A, C, D, E
Step-by-step explanation:
According to the rational root theorem, any rational roots will be of the form ...
±(divisor of the constant)/(divisor of the leading coefficient)
The constant is 8, and its divisors are 1, 2, 4, 8.
The leading coefficient is 6, and its divisors are 1, 2, 3, 6.
So, no rational root will have 3 in the numerator, eliminating choices B and F. The remaining choices are possible rational roots:
Answer:
C
Step-by-step explanation:
Answer:
x=3
Step-by-step explanation:
AB+BC>AC
2x + 3 + x + 1 > x + 10
we correct like terms
2x + x + 3 + 1> x+ 10
3x + 4> x + 10
3x - x > 10-4
2x > 6
divide both sides by 2
2x÷2 > 6÷2
x = 3