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emmasim [6.3K]
3 years ago
12

Add. 523.71 + 0.55 = ?

Mathematics
2 answers:
Crank3 years ago
5 0
532.71
.55
The first step is lining up the decimals.
Then you add like normal
The answer would be 524.26
Zielflug [23.3K]3 years ago
3 0

The Correct Answer Is <u><em>524.26</em></u>

Hope This Helps!!!

-Austint1414

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Eight inches of snow fell in five hours. Write the number of inches per hour.
DedPeter [7]

The answer is 1.6

How I figured it out:

I divided 8 by 5, which gave me 1.6

To make sure this was right, I multiplied 1.6 by 5, which gave me an answer of 8 or other known as 8 inches.

In conclusion, the number of inces per hour is 1.6

6 0
3 years ago
X+3y=5<br> -2x-6y=-10<br><br> Solve using elimination
RSB [31]
Slimination
multiply first equaiton by 2
2x+6y=10
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2x-2x+6y-6y=10-10
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this is true so therfor they are the same equaiton

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x+3y=5
3y=-x+5
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3 0
3 years ago
Consider the following differential equation. x^2y' + xy = 3 (a) Show that every member of the family of functions y = (3ln(x) +
Veronika [31]

Answer:

Verified

y(x) = \frac{3Ln(x) + 3}{x}

y(x) = \frac{3Ln(x) + 3 - 3Ln(3)}{x}

Step-by-step explanation:

Question:-

- We are given the following non-homogeneous ODE as follows:

                           x^2y' +xy = 3

- A general solution to the above ODE is also given as:

                          y = \frac{3Ln(x) + C  }{x}

- We are to prove that every member of the family of curves defined by the above given function ( y ) is indeed a solution to the given ODE.

Solution:-

- To determine the validity of the solution we will first compute the first derivative of the given function ( y ) as follows. Apply the quotient rule.

                          y' = \frac{\frac{d}{dx}( 3Ln(x) + C ) . x - ( 3Ln(x) + C ) . \frac{d}{dx} (x)  }{x^2} \\\\y' = \frac{\frac{3}{x}.x - ( 3Ln(x) + C ).(1)}{x^2} \\\\y' = - \frac{3Ln(x) + C - 3}{x^2}

- Now we will plug in the evaluated first derivative ( y' ) and function ( y ) into the given ODE and prove that right hand side is equal to the left hand side of the equality as follows:

                          -\frac{3Ln(x) + C - 3}{x^2}.x^2 + \frac{3Ln(x) + C}{x}.x = 3\\\\-3Ln(x) - C + 3 + 3Ln(x) + C= 3\\\\3 = 3

- The equality holds true for all values of " C "; hence, the function ( y ) is the general solution to the given ODE.

- To determine the complete solution subjected to the initial conditions y (1) = 3. We would need the evaluate the value of constant ( C ) such that the solution ( y ) is satisfied as follows:

                         y( 1 ) = \frac{3Ln(1) + C }{1} = 3\\\\0 + C = 3, C = 3

- Therefore, the complete solution to the given ODE can be expressed as:

                        y ( x ) = \frac{3Ln(x) + 3 }{x}

- To determine the complete solution subjected to the initial conditions y (3) = 1. We would need the evaluate the value of constant ( C ) such that the solution ( y ) is satisfied as follows:

                         y(3) = \frac{3Ln(3) + C}{3} = 1\\\\y(3) = 3Ln(3) + C = 3\\\\C = 3 - 3Ln(3)

- Therefore, the complete solution to the given ODE can be expressed as:

                        y(x) = \frac{3Ln(x) + 3 - 3Ln(3)}{y}

                           

Download docx
6 0
3 years ago
B) Alfredo said that Angle 7 and Angle 6 are congruent and that would prove Line m
malfutka [58]

Answer:

Yes if Angle 7 and angle 6 are linear pairs in angles created by a straight line that cuts through parallel lines.

Step-by-step explanation:

Remember that two parallel lines that are cut by a transveral will create 8 angles, which will be similar to each other. Making four pairs of congruent angles means that they will be exactly the same angle located in different parts of the system. So if angles 6 and 7 are congruent, and the lines are cut by a transversal, then the lines are parallel.

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3 years ago
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