Question

A 36-g ball at the end of a string is swung in a vertical circle with a radius of 19 cm. The tangential velocity is 200.0 cm/s. Find the tension in the string (express all answers rounded to two decimal points):

Answer 1

Answer:

0.758 N

Explanation:

mass of ball, = 36 g = 0.036 kg

radius, r = 19 cm = 0.19 m

tangential velocity, v = 200 cm / s = 2 m /s

The tension is the string is equal to the centripetal force acting on the ball.

The centripetal force acting on the ball is given by

$T=\frac{mv^{2}}{r}$

$T=\frac{0.036 \times 2 \times 2}{0.19}$

T = 0.758 N

Thus, the tension in the string is given by 0.758 N.