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Triss [41]
1 year ago
12

Calculate the net force acting on the box in the following. refer to the screenshot below.

Physics
1 answer:
Katarina [22]1 year ago
3 0
  • The net force acting on the box is 6N
  • The force are unbalanced

<h3>Explain the concept?</h3>
  • The net force on an object is the sum of all the individual forces acting on it.
  • If two opposing forces act on an object, the net force is the difference between the two forces.
  • When two forces act in the same direction on an object, the net force is the sum of the two forces.

Here the two force 3N and 3N acting on same direction, so

net force = 3N + 3N

                = 6N

Forces that are balanced are those that are opposite in direction and equal in size, but here the equal forces acts in same direction so it is unbalanced

To learn more about net force refer to :

brainly.com/question/18038995

#SPJ13

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Answer:

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Explanation:

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W_g = - \Delta E_p = - (mgh_f  - m g h_i)

where m is the mass of the ball, g is the acceleration due to gravity, h_f is the final height and h_i is the initial height.

So, if the radius is 2.00 m, then the difference of height will be 4 meters:

W_g = - mg (h_f - h_i)

W_g = - 3.00 \ kg \ 9.8 \frac{m}{s^2} \ 4 \m

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As the tension is perpendicular to the velocity of the ball, the force is always perpendicular to the direction of motion. So, the differential of work will be:

dW = \vec{F}  d\vec{r} = 0

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A particle of mass M moves along a straight line with initial speed vi. A force of magnitude F pushes the particle a distance D
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Answer:

Explanation:

Initial kinetic energy of M = 1/2 M vi²

let final velocity be vf

v² = u² + 2a s

vf² =  vi² + 2 (F / M) x D

Kinetic energy

= 1/2 Mvf²

= 1/2 M ( vi² + 2 (F / M) x D

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Ratio with initial value

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3 years ago
Light of wavelength 400 nm is incident on a single slit of width 15 microns. If a screen is placed 2.5 m from the slit. How far
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Answer:

0.0667 m

Explanation:

λ = wavelength of light = 400 nm = 400 x 10⁻⁹ m

D = screen distance = 2.5 m

d = slit width = 15 x 10⁻⁶ m

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θ = angle = ?

Using the equation

d Sinθ = n λ

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