Answer: 
The ball impact velocity i.e(velocity right before landing) is 6.359 m/s
Explanation:
This problem is related to parabolic motion and can be solved by the following equations:
----------------------(1)
---------(2)
 ----------------------- (3)
Where:
x = m is the horizontal distance travelled by the golf ball
 is the golf ball's initial velocity
 is the angle (it was  a horizontal shot)
t is the time
y is the final height of the ball
 is the initial height of the ball
g is the acceleration due gravity
V is the final velocity of the ball
Step 1: finding t 
Let use the equation(2)


s 
Substituting (6) in (1):
-------------------(4)
Step 2:  Finding 
:
From equation(4)


 m/s (8)  
Substituting 
 in (3):
 
v =42 .01 - 15.3566  
V=26.359 m/s
 
        
             
        
        
        
Answer:
m1/m2 = 0.51
Explanation:
First to all, let's gather the data. We know that both rods, have the same length. Now, the expression to use here is the following:
V = √F/u
This is the equation that describes the relation between speed of a pulse and a force exerted on it.
the value of "u" is:
u = m/L
Where m is the mass of the rod, and L the length.
Now, for the rod 1:
V1 = √F/u1 (1)
rod 2:
V2 = √F/u2 (2)
Now, let's express V1 in function of V2, because we know that V1 is 1.4 times the speed of rod 2, so, V1 = 1.4V2. Replacing in the equation (1) we have:
1.4V2 = √F/u1 (3)
Replacing (2) in (3):
1.4(√F/u2) = √F/u1 (4)
Now, let's solve the equation 4:
[1.4(√F/u2)]² = F/u1
1.96(F/u2) =F/u1
1.96F = F*u2/u1
1.96 = u2/u1 (5)
Now, replacing the expression of u into (5) we have the following:
1.96 = m2/L / m1/L
1.96 = m2/m1 (6)
But we need m1/m2 so:
1.96m1 = m2
m1/m2 = 1/1.96
m1/m2 = 0.51
 
        
             
        
        
        
Answer:
unmmmmmmmm I think the answerA
 
        
             
        
        
        
Answer:
88.3
Explanation:
Emf in a rotating coil is given by rate of change of flux:
 E= dФ/dt=(NABcos∅)/ dt
N: number of turns in the coil= 80
A: area of the coil= 0.25×0.40= 0.1
B: magnetic field strength= 1.1
Ф: angle of rotation= 90- 37= 53
dt= 0.06s
E= (80 × 0.4× 0.25×1.10 × cos53)/0.06= 88.3V