The answer for this would be "B".
Answer:
Distance, d = 778.05 m
Explanation:
Given that,
Force acting on the car, F = 981 N
Mass of the car, m = 1550 kg
Initial speed of the car, v = 25 mi/h = 11.17 m/s
We need to find the distance covered by car if the force continues to be applied to the car. Firstly, lets find the acceleration of the car:
Let d is the distance covered by car. Using second equation of motion as :
So, the car will cover a distance of 778.05 meters.
<span>To produce a charge of 1.15 Coulombs in an object, we need to transfer = 1.15/(charge on an electron) number of electrons
As we know that, total charge on an electron = 1.60217662 Ă— 10 ^-19 coulombs
Hence, number of electrons required to move = 1.15/(1.60217662 Ă— 10 ^-19)
= 0.71777 x 10^19 electrons, i.e. 7.17 x 10^18 electrons upto 3 significant figures</span>
Answer:
q = -2.19 x 10⁻⁵ C
Explanation:
Given;
mass of the particle, m = 1.5 g = 0.0015 kg
magnitude of electric field, E = 670 N/C
Electric field is given by;
where;
q is the magnitude of the
f is the force of the charge
f = mg
Since the electric field is acting downward, the force on the charge must be acting upward. Therefore, the charge must be negative
q = -2.19 x 10⁻⁵ C