Answer:
The illumination on the book before the lamp is moved is 9 times the illumination after the lamp is moved.
Explanation:
The distance of the book before the lamp is moved, 
The distance of the book after the lamp is moved, 
Illumination can be given by the formula, 
Illumination before the lamp is moved, 
Illumination after the lamp is moved, 
The illumination on the book before the lamp is moved is 9 times the illumination after the lamp is moved.
Answer:
Accelerates in the same direction as the field
Explanation:
When a charge is immersed in an electric field, the charge experiences an electric force, whose magnitude is given by
F = qE
where q is the magnitude of the charge and E is the magnitude of the electric field.
The direction of the force depends on the sign of the charge. In particular,
- For a positive charge, F and E have the same direction
- For a negative charge, F and E have opposite directions
Therefore, a free positive charge will experience a force in the same direction as the field - therefore, it will accelerate in the same direction.
Answer:
A
Explanation:
Givens
d = 100 meters plus the depth of the well
d = 100 + x where x is the depth of the well.
vi = 0 m/s The object is dropped. It was not thrown.
t = 5 seconds
a = 9.81 m/s^2
formula
d = vi*t + 1/2 a t^2
solution
100 + x = 0 + 1/2 * 9.81 * 5^2
100 + x = 122.625 Subtract 100 from both sides
x = 122.625 - 100
x = 22.6 m
The well is 22.6 meters deep.
(a) 7.18
The electric field within a parallel plate capacitor with dielectric is given by:
(1)
where
is the surface charge density
k is the dielectric constant
is the vacuum permittivity
The area of the plates in this capacitor is
while the charge is
So the surface charge density is
The electric field is
So we can re-arrange eq.(1) to find k:
(b) 
The surface charge density induced on each dielectric surface is given by
where
is the initial charge density
k = 7.18 is the dielectric constant
Substituting,
And by multiplying by the area, we find the charge induced on each surface:
