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Kipish [7]
3 years ago
8

What is the magnitude of the force that lifts a 3-kilogram object straight upwards?

Physics
2 answers:
Tanya [424]3 years ago
6 0
I think these questions answer is a
frez [133]3 years ago
4 0

Any force of 29.4 Newtons or greater can do it.

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Optical tweezers use light from a laser to move single atoms and molecules around. Suppose the intensity of light from the tweez
katrin [286]

Answer:

a= 4.4×10 m/s^2

Explanation:

pressure P  = E/c

Where, E = 100 W/m^2 intensity of light

c= speed of light  = 3×10^8 m/s

P = 1000/ 3×10^8

P = 3.33×10^(-6) Pa

Force F = P×A

  • P is the pressure and c= speed of light

F = 3.33×10^{-6}×6.65×10(-29)

= 2.22×10^{-6}

acceleration a  = F/m = 2.22×10^{-6}/ 5.10×10^{-27}

a= 4.4×10 m/s^2

4 0
3 years ago
Typically, water runs through the baseboard copper tubing and, therefore, fresh hot water is constantly running through the pipi
Bas_tet [7]

Answer: The temperature of the water falls by 3.3°C

Explanation:

The heat change is related to the change in temperature by the equation

dH = m Cp dT

In this example, -2665 J = 193 g x 4.184 J/g°C x dT

so dT = -3.3 °C

3 0
3 years ago
A 6.8 kg bowling ball and 7.4 kg bowling ball rest on a rack 0.74 m apart. What is the force of gravity pulling each ball toward
zimovet [89]

The gravitational force between the two balls is 6.13\cdot 10^{-9} N

Explanation:

The magnitude of the gravitational force between two objects is given by:

F=G\frac{m_1 m_2}{r^2}

where :

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between the objects

For the balls in this problem,  we have

m_1 = 6.8 kg

m_2 = 7.4 kg

r = 0.74 m

Substituting into the equation, we find the gravitational force between the two balls:

F=(6.67\cdot 10^{-11})\frac{(6.8)(7.4)}{(0.74)^2}=6.13\cdot 10^{-9}N

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

4 0
3 years ago
A delta connection has a voltage of 560 V connected to it. How much voltage is dropped across each phase
SashulF [63]

Answer:

E_Phase = 560V

Explanation:

The computation of the voltage i.e. dropped across each phase is shown below:

Given that

The delta connection line voltage is

E_line = 560 V

And, in the case of delta connection, the line voltage would be equivalent to the phase voltage

That means

E_Phase = E_Line

= 560 V

Hence, the voltage i.e. dropped across each phase is

E_Phase = 560V

5 0
3 years ago
Which form of energy moves spontaneously from hot objects to cold objects?
Mumz [18]

Answer:

heat

Explanation:

google ( ╹▽╹ )✧◝(⁰▿⁰)◜✧

6 0
3 years ago
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