4 equal side,2 opposite side parallel, no right angle

Find a solution to the linear equation y=6x−18 by filling in the boxes with a valid value of x and y.

juin [17]

You can choose any value for x and find the corresponding y value. So let’s assume x=1.

y=6x-18
y=6(1)-18
y=6-18
y=-12

So a correct ordered pair would be (1,-12).

7 0

3 years ago

12.5% of $100 is what number? percent proption

scoray [572]

Answer: $12.5

Step-by-step explanation:

The $100 Is 100 percent meaning that one percent is $1. Take that and multiply it by 12.5 and get $12.5

6 0

3 years ago

Read 2 more answers

A small tree was planted at a height of 10 feet. The tree has been planted for 14 months, and is now 49.2 feet tall. Which equat

Crank

The equation is x=(49.2-10)/14

6 0

4 years ago

......................,.,................

Alex787 [66]

a=6, b=2

Step-by-step explanation:

Use simplification into substitution
$\frac{a}{3} =1+\frac{2}{b}$

$a=3(1+\frac{2}{b})$

$a=3+\frac{6}{b}$

We can now plug this value of <em>a</em> into the second equation.

$\frac{3+\frac{6}{b} }{4} +\frac{3}{b} =3$

Get rid of fractions in the numerators and/or denominators

$\frac{3b+6}{4b} +\frac{3}{b} =3$

Then we can match the denominators

$\frac{3b+6}{4b} +\frac{12}{4b} =3$

Combine

$\frac{3b+18}{4b} =3$

Divide both sides by three

$\frac{b+6}{4b} =1$

Get rid of fractions

$b+6=4b$

Single out <em>b</em>

$6=3b$

$b=2$

Now we can plug it into the equation

$\frac{a}{3} -\frac{2}{2} =1$

$\frac{a}{3} =2$

$a=6$

Now we can check it;

$\frac{6}{3} -\frac{2}{2} =1$

↑CORRECT

$\frac{6}{4} +\frac{3}{2} =3$

↑CORRECT

4 0

2 years ago

What is the solution to the system of equations Use the substitution method to solve the system of equations. Show your work.

marishachu [46]

Answer:

Step-by-step explanation:

Let's work to solve this system of equations:

y = 2x ~~~~~~~~\gray{\text{Equation 1}}y=2x Equation 1

x + y = 24 ~~~~~~~~\gray{\text{Equation 2}}x+y=24 Equation 2

The tricky thing is that there are two variables, xx and yy. If only we could get rid of one of the variables...

Here's an idea! Equation 11 tells us that \goldD{2x}2x and \goldD yy are equal. So let's plug in \goldD{2x}2x for \goldD yy in Equation 22 to get rid of the yy variable in that equation:

\begin{aligned} x + \goldD y &= 24 &\gray{\text{Equation 2}} \\\\ x + \goldD{2x} &= 24 &\gray{\text{Substitute 2x for y}}\end{aligned}

x+y

x+2x

=24

Equation 2

Substitute 2x for y

Brilliant! Now we have an equation with just the xx variable that we know how to solve:

x+2x3x 3x3x=24=24=243=8Divide each side by 3

Nice! So we know that xx equals 88. But remember that we are looking for an ordered pair. We need a yy value as well. Let's use the first equation to find yy when xx equals 88:

\begin{aligned} y &= 2\blueD x &\gray{\text{Equation 1}} \\\\ y &= 2(\blueD8) &\gray{\text{Substitute 8 for x}}\\\\ \greenD y &\greenD= \greenD{16}\end{aligned}

y

=2x

=2(8)

=16

Equation 1

Substitute 8 for x

Sweet! So the solution to the system of equations is (\blueD8, \greenD{16})(8,16). It's always a good idea to check the solution back in the original equations just to be sure.

Let's check the first equation:

\begin{aligned} y &= 2x \\\\ \greenD{16} &\stackrel?= 2(\blueD{8}) &\gray{\text{Plug in x = 8 and y = 16}}\\\\ 16 &= 16 &\gray{\text{Yes!}}\end{aligned}

y

16

=2x

=

?

2(8)

=16

Plug in x = 8 and y = 16

Yes!

Let's check the second equation:

\begin{aligned} x +y &= 24 \\\\ \blueD{8} + \greenD{16} &\stackrel?= 24 &\gray{\text{Plug in x = 8 and y = 16}}\\\\ 24 &= 24 &\gray{\text{Yes!}}\end{aligned}

x+y

8+16

24

=24

=

?

24

=24

Plug in x = 8 and y = 16

Yes!

Great! (\blueD8, \greenD{16})(8,16) is indeed a solution. We must not have made any mistakes.

Your turn to solve a system of equations using substitution.

Use substitution to solve the following system of equations.

4x + y = 284x+y=28

y = 3xy=3x

7 0

4 years ago