Answer:
They apear this way because of refraction
Explanation:
<span>The maximum number of electrons that can be contained in an energy level (also called shells) is determined by the formula 2n^2, where n is the energy level; So, when n = 1, the maximum number of electrons is 2; when n = 2, the maximum number of electrons is 2*(2^2) = 8; when n = 3, the maximum number of electrons is 2 * (3^2) = 18; and when n=4, the maximum number of electrons is 2(4^2) = 32. So, briefly the series is 2, 8, 16, 32.</span>
Answer:
Explanation:
Incorrect name correct name
a) calcium dichloride calcium chloride
b) copper(II) oxide copper(I) oxide
c) stannous tetrafluoride stannic fluoride
d) hydrogen chloride acid hydrochloric acid
A chemestretic equation equation which is formed by h20 mc square hydrogen peroxide and the equation of cf6c7bu7c
Hope it helped
Answer:
Empirical formula: BH3
Molecular Formula: B2H6
Explanation:
To solve the exercise, we need to know how many boron atoms and how many hydrogen atoms the compound has. We know that of the total weight of the compound, 78.14% correspond to boron and 21.86% to hydrogen. As the weight of the compound is between 27 g and 28 g, using the above percentages we can solve that the compound has between 21.1 g and 21.8 g of boron, and between 5.9 g and 6.1 g of hydrogen:
100% _____ 27 g
78.14% _____ x = 78.14% * 27g / 100% = 21.1 g boron
100% ______27 g
21.86% ______ x = 21.86% * 27g / 100% = 5.9 g hydrogen
100% _____ 28 g
78.14% _____ x = 78.14% * 28g / 100% = 21.8 g boron
100% _____ 28g
21.86% _____ x = 21.86% * 28g / 100% = 6.1 g hydrogen
So, if the atomic weight of boron is 10.8 g, there must be two boron atoms in the compound that sum 21.6 g. The weight of hydrogen is 1 g, so the compound must have six hydrogen atoms.
The molecular formula represents the real amount of atoms that form a compound. Therefore, the molecular formula of the compound is B2H6.
The empirical formula is the minimum expression that represents the proportion of atoms in a compound. For example, ethane has 2 carbon atoms and 6 hydrogen atoms, so its molecular formula is C2H6, however, its empirical formula is CH3. Therefore, the empirical formula of the boron compound is BH3.
