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sdas [7]
3 years ago
5

Three students are working with different substances to measure the chemical changes that occur. Chao is working with milk, Mia

is working with carbon dioxide gas, and Ezra is working with rock. Which would best describe the way to treat each substance to get a faster reaction? Chao should change the temperature, Mia should adjust the pressure, and Ezra should increase the surface area. Chao should change the concentration, Mia should adjust the temperature, and Ezra should increase the surface area. Chao should change the temperature, Mia should adjust the concentration, and Ezra should decrease the surface area. Chao should change the concentration, Mia should adjust the pressure, and Ezra should decrease the surface area.
Chemistry
2 answers:
yawa3891 [41]3 years ago
4 0
For chao who is working  with milk, he should adjust the temperature of the milk to have a faster reaction. for ezra who is working with rock, she must increase the surface area of the rock to increase the reaction rate, this can be done by grinding. and for mia who is working with carbon dioxide gas, she should adjust the pressure
yanalaym [24]3 years ago
4 0

The answer is: Chao should change the temperature, Mia should adjust the pressure, and Ezra should increase the surface area.

Milk is a liquid, carbon dioxide is a gas and rock is a solid.

The increase in energy will cause the reactants particles to move faster, which will increase their temperature and lead to a faster reaction rate.

The reaction rate is the speed at which reactants are converted into products.

The collision theory states that a certain fraction of the collisions (successful collisions) cause significant chemical change.  

The successful collisions must have enough energy (activation energy).  

If the surface area and temperature are increased, speed of reaction also increased.

Particles are in constant, random motion and possess kinetic energy, molecules faster and have more collisions.  

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Answer:

0.286 mN/m^2

Explanation:

Using Laplace's law of surface tension:

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P =  \frac{2*25mN/m}{0.07*10^{-2}m}

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In the smaller alveoli with radius 0.05 mm = 0.05 * 10^{-2} m; we have:

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5 0
3 years ago
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