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sdas [7]
3 years ago
5

Three students are working with different substances to measure the chemical changes that occur. Chao is working with milk, Mia

is working with carbon dioxide gas, and Ezra is working with rock. Which would best describe the way to treat each substance to get a faster reaction? Chao should change the temperature, Mia should adjust the pressure, and Ezra should increase the surface area. Chao should change the concentration, Mia should adjust the temperature, and Ezra should increase the surface area. Chao should change the temperature, Mia should adjust the concentration, and Ezra should decrease the surface area. Chao should change the concentration, Mia should adjust the pressure, and Ezra should decrease the surface area.
Chemistry
2 answers:
yawa3891 [41]3 years ago
4 0
For chao who is working  with milk, he should adjust the temperature of the milk to have a faster reaction. for ezra who is working with rock, she must increase the surface area of the rock to increase the reaction rate, this can be done by grinding. and for mia who is working with carbon dioxide gas, she should adjust the pressure
yanalaym [24]3 years ago
4 0

The answer is: Chao should change the temperature, Mia should adjust the pressure, and Ezra should increase the surface area.

Milk is a liquid, carbon dioxide is a gas and rock is a solid.

The increase in energy will cause the reactants particles to move faster, which will increase their temperature and lead to a faster reaction rate.

The reaction rate is the speed at which reactants are converted into products.

The collision theory states that a certain fraction of the collisions (successful collisions) cause significant chemical change.  

The successful collisions must have enough energy (activation energy).  

If the surface area and temperature are increased, speed of reaction also increased.

Particles are in constant, random motion and possess kinetic energy, molecules faster and have more collisions.  

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Dmitrij [34]

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hope this helps xx

3 0
3 years ago
I am confused. Can yall help me answer this question? Also if you do, please show your work.
Eva8 [605]
Answer is: <span>volume of the acid is 0,075 L.
</span>Chemical reaction: KOH + HCl → KCl + H₂O.
V(KOH) = 30 mL · 0,001 L/mL = 0,3 L.
c(KOH) = 0,5 M = 0,5 mol/L.
c(HCl) = 2 M = 2 mol/L.
V(HCl) = ?
From chemical reaction n(KOH) : n(HCl) = 1 : 1.
n(KOH) = n(HCl).
c(KOH) · V(KOH) = c(HCl) · V(HCl).
0,5M · 0,3 L = 2M · V(HCl).
V(HCl) = 0,075 L.
8 0
3 years ago
in the diagram shown below, the blue light ray represents a ray of light incident on a boundary between media. the diagram repre
Zigmanuir [339]

Answer:

I can't see the diagram please

6 0
2 years ago
The rate of effusion of oxygen to an unknown gas is 0.935. what is the other gas?
Kamila [148]

Answer:

N2

Explanation:

Rate of effusion is defined by Graham's Law:  

(Rate 1/Rate 2) = (sqrt (M2)/ sqrt (M1))

(Where M is the molar mass of each substance. )

Molar Mass of oxygen, O2, is 32 (M1).

Rate of effusion of O2 to an unknown gas is .935(Rate 1).  

Rate 2 is unknown so put 1.

Solve for x (M2).

.935/1 = sqrt x/ sqrt32

.935 x sqrt 32 = sqrt x

5.29 = sq rt x

5.29^2 = 27.975 = 28  

N2 has a molar mass of 28 so it is the correct gas.

4 0
3 years ago
Salt is often added to water to raise the boiling point to heat food more quickly. if you add 30.0g of salt to 3.75kg of water,
sammy [17]

Assuming an ebullioscopic constant of 0.512 °C/m for the water, If you add 30.0g of salt to 3.75kg of water, the boiling-point elevation will be 0.140 °C and the boiling-point of the solution will be 100.14 °C.

<h3>What is the boiling-point elevation?</h3>

Boiling-point elevation describes the phenomenon that the boiling point of a liquid will be higher when another compound is added, meaning that a solution has a higher boiling point than a pure solvent.

  • Step 1: Calculate the molality of the solution.

We will use the definition of molality.

b = mass solute / molar mass solute × kg solvent

b = 30.0 g / (58.44 g/mol) × 3.75 kg = 0.137 m

  • Step 2: Calculate the boiling-point elevation.

We will use the following expression.

ΔT = Kb × m × i

ΔT = 0.512 °C/m × 0.137 m × 2 = 0.140 °C

where

  • ΔT is the boiling-point elevation
  • Kb is the ebullioscopic constant.
  • b is the molality.
  • i is the Van't Hoff factor (i = 2 for NaCl).

The normal boiling-point for water is 100 °C. The boiling-point of the solution will be:

100 °C + 0.140 °C = 100.14 °C

Assuming an ebullioscopic constant of 0.512 °C/m for the water, If you add 30.0g of salt to 3.75kg of water, the boiling-point elevation will be 0.140 °C and the boiling-point of the solution will be 100.14 °C.

Learn more about boiling-point elevation here: brainly.com/question/4206205

7 0
2 years ago
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