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Jobisdone [24]
3 years ago
10

Which of the following is an input for cellular respiration? a. CO2 b. H2O c. sunlight d. O2 Please select the best answer from

the choices provided A B C D
Chemistry
2 answers:
Westkost [7]3 years ago
5 0
The output CO2 but the input is O2
hope it helps
Verdich [7]3 years ago
5 0

Answer : The correct option is, (d) O_2

Explanation :

Cellular respiration : It is a type of process in which the glucose molecule react with the oxygen to form a great amount of energy in the form of ATP and carbon dioxide and water as a byproducts.

The balanced equation for cellular respiration will be,

C_6H_{12}O_6+6O_2\rightarrow 6CO_2+6H_2O+ATP

Food as a glucose and oxygen are the input for the cellular respiration.

Hence, the correct option is, (d) O_2

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Read 2 more answers
51. The radius of gold is 144 pm and the density is 19.32 g/cm3. Does elemental gold have a face-centered cubic structure or a b
Serjik [45]

Answer:

Elemental gold to have a Face-centered cubic structure.

Explanation:

From the information given:

Radius of gold = 144 pm

Its density = 19.32 g/cm³

Assuming the structure is a face-centered cubic structure, we can determine the density of the crystal by using the following:

a = \sqrt{8} r

a = \sqrt{8} \times 144 pm

a = 407 pm

In a unit cell, Volume (V) = a³

V = (407 pm)³

V = 6.74 × 10⁷ pm³

V = 6.74 × 10⁻²³ cm³

Recall that:

Net no. of an atom in an FCC unit cell = 4

Thus;

density = \dfrac{mass}{volume}

density = \dfrac{ 4 \ atm ( 196.97 \ g/mol) (\dfrac{1 \ mol }{6.022 \times 10^{23} \ atoms})}{6.74 \times 10^{-23} \ cm^3}

density d = 19.41 g/cm³

Similarly; For a  body-centered cubic structure

r = \dfrac{\sqrt{3}}{4}a

where;

r = 144

144 = \dfrac{\sqrt{3}}{4}a

a = \dfrac{144 \times 4}{\sqrt{3}}

a = 332.56 pm

In a unit cell, Volume V = a³

V = (332.56 pm)³

V = 3.68 × 10⁷ pm³

V  3.68 × 10⁻²³   cm³

Recall that:

Net no. of atoms in BCC cell = 2

∴

density = \dfrac{mass}{volume}

density = \dfrac{ 2 \ atm ( 196.97 \ g/mol) (\dfrac{1 \ mol }{6.022 \times 10^{23} \ atoms})}{3.68 \times 10^{-23} \ cm^3}

density =17.78 g/cm³

From the two calculate densities, we will realize that the density in the face-centered cubic structure is closer to the given density.

This makes the elemental gold to have a Face-centered cubic structure.

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3 years ago
Which of these is NOT a colloid?
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Answer:C

Explanation:

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A compound contains 72% magnesium and 28% nitrogen. What is its empirical formula?
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So the empirical formula is Mg3N2

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