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Jobisdone [24]
3 years ago
10

Which of the following is an input for cellular respiration? a. CO2 b. H2O c. sunlight d. O2 Please select the best answer from

the choices provided A B C D
Chemistry
2 answers:
Westkost [7]3 years ago
5 0
The output CO2 but the input is O2
hope it helps
Verdich [7]3 years ago
5 0

Answer : The correct option is, (d) O_2

Explanation :

Cellular respiration : It is a type of process in which the glucose molecule react with the oxygen to form a great amount of energy in the form of ATP and carbon dioxide and water as a byproducts.

The balanced equation for cellular respiration will be,

C_6H_{12}O_6+6O_2\rightarrow 6CO_2+6H_2O+ATP

Food as a glucose and oxygen are the input for the cellular respiration.

Hence, the correct option is, (d) O_2

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Which interactions and processes contribute to the dissolution of ionic compounds in water?
Tanya [424]

Explanation:

Polarity is defined as the development of partial charges on the atoms of a molecule. In a water molecule, there are hydrogen and oxygen atoms.

Due to the difference in electronegativity of both hydrogen and oxygen atom there is development of partial positive charge on hydrogen atom and a partial negative charge on oxygen atom.  

So, when bond between hydrogen and oxygen will break down then it will form hydrogen ions (H^{+}) and oxygen ions (O^{2-}).

Ion-dipole interactions are defined as the interactions that occur when an ion interacts with the dipole of a molecule.

When an electron is added to a neutral atom to convert it into a negative ion then the amount of change taking place in its energy is known as electron affinity.

So, oxygen atom has an affinity towards cations and hydrogen atom has an affinity for anions.

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2. Ion–dipole interactions

4. Hydration

6. Affinity of hydrogen towards anions

3 0
3 years ago
How many milliliters of sodium metal, with a density of 0.97 g/mL, would be needed to produce 43.6 grams of sodium hydroxide in
GaryK [48]

Answer is: 25.84  milliliters of sodium metal.

Balanced chemical reaction: 2Na + 2H₂O → 2NaOH + H₂.

d(Na) = 0.97 g/mL; density of sodim.

m(NaOH) = 43.6 g; mass of sodium hydroxide.

n(NaOH) = m(NaOH) ÷ M(NaOH).

n(NaOH) = 43.6 g ÷ 40 g/mol.

n(NaOH) =1.09 mol; amount of sodium hydroxide.

From chemical reaction: n(NaOH) : n(Na) = 2 : 2 (1: 1).

n(Na) = 1.09 mol.

m(Na) = 1.09 mol · 23 g/mol.

m(Na) = 25.07 g; mass of sodium.

V(Na) = m(Na) ÷ d(Na).

V(Na) = 25.07 g ÷ 0.97 g/mL.

V(Na) = 25.84 mL.

7 0
3 years ago
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