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Jobisdone [24]
3 years ago
10

Which of the following is an input for cellular respiration? a. CO2 b. H2O c. sunlight d. O2 Please select the best answer from

the choices provided A B C D
Chemistry
2 answers:
Westkost [7]3 years ago
5 0
The output CO2 but the input is O2
hope it helps
Verdich [7]3 years ago
5 0

Answer : The correct option is, (d) O_2

Explanation :

Cellular respiration : It is a type of process in which the glucose molecule react with the oxygen to form a great amount of energy in the form of ATP and carbon dioxide and water as a byproducts.

The balanced equation for cellular respiration will be,

C_6H_{12}O_6+6O_2\rightarrow 6CO_2+6H_2O+ATP

Food as a glucose and oxygen are the input for the cellular respiration.

Hence, the correct option is, (d) O_2

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5 0
3 years ago
Consider the following reaction 2 N2O(g) => 2 N2(g) + O2(g) rate = k[N2O]. For an initial concentration of N2O of 0.50 M, cal
den301095 [7]

Answer:

After 2.0 minutes the concentration of N2O is 0.3325 M

Explanation:

Step 1: Data given

rate = k[N2O]

initial concentration of N2O of 0.50 M

k = 3.4 * 10^-3/s

Step 2: The balanced equation

2N2O(g) → 2 N2(g) + O2(g)  

Step 3: Calculate the concentration of N2O after 2.0 minutes

We use the rate law to derive a time dependent equation.

-d[N2O]/dt = k[N2O]

ln[N2O] = -kt + ln[N2O]i

 ⇒ with k = 3.4 *10^-3 /s

⇒ with t = 2.0 minutes = 120s

⇒ with [N2O]i = initial conc of N2O = 0.50 M

ln[N2O] = -(3.4*10^-3/s)*(120s) + ln(0.5)

ln[N2O] = -1.101

e^(ln[N2O]) = e^(-1.1011)

[N2O} = 0.3325 M

After 2.0 minutes the concentration of N2O is 0.3325 M

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3 years ago
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7 0
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