I need help please

The function The function p(t)=4+2(t−1) represents the number of people who can be seated at an event. The total of t tables are

Mamont248 [21]

The correct statements about the scenario are;

The function is an arithmetic sequence
The number 2 is the number of tables added when t increases by 1.
The number 4 represents the number of people that can be seated at an event if only 1 table is available.

According to the function given;

p(t)=4+2(t−1)

Evidently, the function, p(t) represents the number of people that can sit when t tables are available.

T(n) = a + d(n -1)

In essence, the function resembles that of a general arithmetic progression with first term, a = 4.

The common difference, d = 2.

The statements which are correct are therefore as listed above.

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5 0

3 years ago

In ΔSTU, m∠S=(11x+3)∘,∠T=(2x+16)∘, and m∠U=(x+7)∘. Find .

frozen [14]

Answer:

x = 11

Step-by-step explanation:

In ΔSTU ,

m∠S = (11x+3)° ; m∠T = (2x+16)° ; m∠U = (x+7)°

According to angle sum property of a triangle , sum of all the interior angles of the triangle is 180°.

So,

$11x + 3 + 2x + 16 + x + 7 = 180$

$= > 14x + 26 = 180$

$= > 14x = 180 - 26 = 154$

$= > x = \frac{154}{14} = 11$

6 0

3 years ago

In a randomly selected sample of 100 students at a University, 81 of them had access to a computer at home. Give the value of th

astra-53 [7]

Answer:

The value of the standard error for the point estimate is of 0.0392.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$