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Kruka [31]
3 years ago
10

The fusion of the common hepatic duct and the cystic duct forms the

Biology
2 answers:
kupik [55]3 years ago
8 0
<span>The fusion of the common hepatic duct and the cystic duct forms the common bile duct. The common bile duct carries bile from the gallbladder and empties it into the small intestine, specifically the duodenum. It is also known as the choledochus. It is part of the biliary duct system. </span>
laiz [17]3 years ago
6 0

Common bile duct

Common bile duct is formed by the fusion of the common hepatic duct and the cystic duct. Common bile duct functions by transporting bile from the gallbladder and releasing it into the duodenum. The common hepatic duct and the cystic duct that forms common bile duct are enclosed by the muscular sphincter of Oddi.






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Observation.most plant have green leaves <br> Hypothesis:?
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Question 1 Life would cease to exist without energy from the sun or some other source.
malfutka [58]

Answer:

Q1) True

Q2) Metabolism

Q3) Physiological response

Explanation:

Q1) Energy cannot be created (first law of thermodynamics). Life needs an energy source to transform. Without the energy from the sun or any other sources, life would cease to exist. (True)

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5 0
3 years ago
In a diploid species of plant, the genes for plant height and fruit shape are syntenic and separated by 18 m.u. Allele D produce
FinnZ [79.3K]

Answer:

C)Parental: 41% Dr, 41% dR; recombinant: 9% DR, 9% dr.

Explanation:

The notation Dr/dR for genotypes means that one homologous chromosome has the alleles Dr and the other homologous chromosome has the alleles dR.

The heterozygous plant  Dr/dR will produce 4 types of gametes: two identical to the chromosmes the individual has in its somatic cells (called parental), and two gametes which will be a mix of the alleles in the homologous chromosomes (called recombinant).

  • Dr: parental
  • dR: parental
  • DR: recombinant
  • dr: recombinant

To calculate the frequency of each type of gamete, we must use the formula:

Distance (map units) / 100 = frequency of recombination.

18 mu / 100 = 0.18.

The total frequency of recombination between the genes D and R is 0.18, but every time crossing over happens, two recombinant gametes are generated. Therefore, each recombinant gamete will have a frequency of 0.18/2=0.09 = 9%.

The frequency of parental gametes will be:

1 - frequency of recombinant gametes

1 - 0.18 = 0.82

But there are 2 parental gametes, so each of them will have a frequency of 0.82/2=0.41 = 41%.

6 0
3 years ago
Decrease 120 by 15%
WITCHER [35]

Answer:

its e (102)

Explanation:

3 0
3 years ago
Read 2 more answers
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