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Alex
2 years ago
12

HElp me plzzzzz??????

Chemistry
1 answer:
iris [78.8K]2 years ago
4 0

Answer:

The answer to your question is given below

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

Zn + 2HCl —> ZnCl2 + H2

Thus, we can write out the atoms present in both the reactant and the product by doing a simple head count. The atoms present are listed below:

Element >>> Reactant >>> Product

Zn >>>>>>>> 1 >>>>>>>>>> 1

H >>>>>>>>> 2 >>>>>>>>> 2

Cl >>>>>>>>> 2 >>>>>>>>> 2

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1)petroleum and natural gas are formed in the__________
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he population of the Earth is roughly eight billion people. If all free electrons contained in this extension cord are evenly sp
wolverine [178]

1) Drift velocity: 3.32\cdot 10^{-4}m/s

2) 5.6\cdot 10^{13} electrons per person

Explanation:

1)

For a current flowing through a conductor, the drift velocity of the electrons is given by the equation:

v_d=\frac{I}{neA}

where

I is the current

n is the concentration of free electrons

e=1.6\cdot 10^{-19}C is the electron charge

A is the cross-sectional area of the wire

The cross-sectional area can be written as

A=\pi r^2

where r is the radius of the wire. So the equation becomes

v_d=\frac{I}{ne\pi r^2}

In this problem, we have:

I = 8.0 A is the current

8.5\cdot 10^{28} m^{-3} is the concentration of free electrons

d = 1.5 mm is the diameter, so the radius is

r = 1.5/2 = 0.75 mm = 0.75\cdot 10^{-3}m

Therefore, the drift velocity is:

v_d=\frac{8.0}{(8.5\cdot 10^{28})(1.6\cdot 10^{-19})\pi(0.75\cdot 10^{-3})^2}=3.32\cdot 10^{-4}m/s

2)

The total length of the cord in this problem is

L = 3.00 m

While the cross-sectional area is

A=\pi r^2=\pi (0.75\cdot 10^{-3})^2=1.77\cdot 10^{-6} m^2

Therefore, the volume of the cord is

V=AL (1)

The number of electrons per unit volume is n, so the total number of electrons in this cord is

N=nV=nAL=(8.5\cdot 10^{28})(1.77\cdot 10^{-6})(3.0)=4.5\cdot 10^{23}

In total, the Earth population consists of 8 billion people, which is

N'=8\cdot 10^9

Therefore, the number of electrons that each person would get is:

N_e = \frac{N}{N'}=\frac{4.5\cdot 10^{23}}{8\cdot 10^9}=5.6\cdot 10^{13}

7 0
3 years ago
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