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olasank [31]
3 years ago
5

1.3-3 Determine whether each of the following statements is true or false. If the statement is false, demonstrate this by proof

or example. (a) Every continuous-time signal is an analog signal. (b) Everydiscrete-timesignalisadigitalsignal. (c) If a signal is not an energy signal, then it must be a power signal and vice versa. (d) An energy signal must be of finite duration. (e) A power signal cannot be causal. (f) A periodic signal cannot be anticausal

Chemistry
1 answer:
Inga [223]3 years ago
3 0

Answer:

(a)False (b)False (c)False (d)False (e)False

Explanation:

a) Continuous time signal can also be digital. e.g continuous time square waveform (see first picture)

b) A discrete time signal can also be analog. e.g discrete time exponential function can take any value (see second picture)

c) When both energy and power of signal are infinite, it is neither power signal nor energy signal e.g ramp signals, e^{t}u(t) signal

d)A signal of infinite length can also have finite energy. e. g e^{t}u(t)

e)Step waveform u(t) is a power signal but also causal

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Answer:

There are 5 neutrons in beryllium

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3 years ago
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Answer A B C and D please for my chemistry hw
r-ruslan [8.4K]

<u>Answer:</u> The equations are provided below.

<u>Explanation:</u>

Skeleton equations are defined as the equations which simply indicate the molecules that are involved in a chemical reaction. These equations are unbalanced equations.

Balanced equations are defined as the chemical equation in which number of individual atoms on the reactant side must be equal to the number of individual atoms on the product side.

  • For A:

Water decomposes in the direct current to form hydrogen and oxygen.

Skeleton Equation: H_2O(l)\rightarrow H_2(g)+O_2(g)

Balanced Equation: 2H_2O(l)\rightarrow 2H_2(g)+O_2(g)

  • For B:

Mercury (II) oxide decomposes in heat to form mercury, oxygen.

Skeleton Equation: HgO(s)\rightarrow Hg+O_2

Balanced Equation: 2HgO(s)\rightarrow 2Hg+O_2

  • For C:

Calcium carbonate when heated forms calcium oxide and carbon dioxide.

Skeleton Equation: CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

Balanced Equation: CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

  • For D:

Group 2 hydroxides, when heated forms oxide and water vapor.

Skeleton Equation: Ca(OH)_2\rightarrow CaO+H_2O

Balanced Equation: Ca(OH)_2\rightarrow CaO+H_2O

3 0
3 years ago
How many sodium ions are in 4543.3 g of NaCl?
Stella [2.4K]

Answer:

4.68x10²⁵ ions of Na⁺

Explanation:

First of all, we dissociate the salt:

NaCl(aq) → Na⁺(aq) + Cl⁻(aq)

An aqueous solution of NaCl dissociates in chlorides anions and sodium cations. Ratio is 1:1, per 1 mol of NaCl, we have 1 mol of Na⁺

We determine the moles of salt: 4543.3 g . 1mol / 58.45 g = 77.7 moles

77.7 moles are the amount of NaCl, therefore we have 77.7 moles of Na⁺.

We count the ions:

1 mol fo Na⁺ has 6.02x10²³ ions

77.7 moles of Na⁺ must have (77.7 . 6.02x10²³) / 1 = 4.68x10²⁵ ions of Na⁺

3 0
3 years ago
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If a piece of cadmium with a mass of 37.60 g and a temperature of 100.0 oC is dropped into 25.00 cc of water at 23.0 oC, what wi
zlopas [31]

Answer:

T_{eq}=28.9\°C

Explanation:

Hello!

In this case, since it is observed that hot cadmium is placed in cold water, we can infer that the heat released due to the cooling of cadmium is gained by the water and therefore we can write:

Q_{Cd}+Q_{W}=0

Thus, we insert mass, specific heat and temperatures to obtain:

m_{Cd}C_{Cd}(T_{eq}-T_{Cd})+m_{W}C_{W}(T_{eq}-T_{W})=0

In such a way, since the specific heat of cadmium and water are respectively 0.232 and 4.184 J/(g °C), we can solve for the equilibrium temperature (the final one) as shown below:

T_{eq}=\frac{m_{Cd}C_{Cd}T_{Cd}+m_{W}C_{W}T_{W}}{m_{Cd}C_{Cd}+m_{W}C_{W}}

Now, we plug in to obtain:

T_{eq}=\frac{37.60g*0.232\frac{J}{g\°C}*100.00\°C+25.00g*4.184\frac{J}{g\°C}*23.0\°C}{37.60g*0.232\frac{J}{g\°C}+25.00g*4.184\frac{J}{g\°C}}\\\\T_{eq}=28.9\°C

NOTE: since the density of water is 1g/cc, we infer that 25.00 cc equals 25.00 g.

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