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Anna35 [415]
3 years ago
11

Which equations shows the complete dissociation of a strong base?

Chemistry
1 answer:
tensa zangetsu [6.8K]3 years ago
4 0
The correct answer is the fourth option. The complete dissociation of a strong base is BOH + h20 -> B+ + OH- + H20 since this is the only base from the choices given. A base is a substance that accepts hydrogen ions. 
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The volume of a gas is 4.0 L when the pressure is 1.00 atm. At the same temperature, what is the pressure at which the volume of
Leokris [45]

<u>Answer:</u> 2.00 atm

<u>Explanation:</u>

The gas is kept under the same temperature in this problem. Assuming the amount of gas is constant, we can apply the Boyle's law.

The Boyle's law equation,

P₁V₁ =  P₂V  ₂

Plug in the values,

1.00 atm x 4.0 L =  P₂  x 2.0 L

Simplify,

4.00 atm L = 2  P₂ L

Now flip the equation,

2  P₂ L = 4.00 atm L

Dividing both sides by 2 we get,

P₂ = 2.00 atm

8 0
3 years ago
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mario62 [17]
False would be the answer
6 0
3 years ago
Read 2 more answers
5. What is the mass of 9.80 x 1023 formula units of zinc chlorate, Zn(CO3)2?
Zielflug [23.3K]

Answer:

\boxed{\text{378 g}}

Explanation:

We must convert formula units of Zn(ClO₃)₂ to moles and then to grams of Zn(ClO₃)₂.

Step 1. Convert formula units to moles

\text{Moles of Zn(ClO$_{3}$)$_{2}$}\\\\= 9.80 \times10^{23}\text{ formula units Zn(ClO$_{3}$)$_{2}$} \times \dfrac{\text{1 mol Zn(ClO$_{3}$)$_{2}$}}{6.022 \times\ 10^{23} \text{ formula units Zn(ClO$_{3}$)$_{2}$}}\\\\= \text{1.627 mol Zn(ClO$_{3}$)$_{2}$}

Step 2. Convert moles to grams

\text{Mass of Zn(ClO$_{3}$)$_{2}$}\\\\= \text{1.627 mol Zn(ClO$_{3}$)$_{2}$} \times \dfrac{\text{232.29 g Zn(ClO$_{3}$)$_{2}$}}{\text{1 mol Zn(ClO$_{3}$)$_{2}$}}\\\\= \text{378 g Zn(ClO$_{3}$)$_{2}$}\\\\\text{The mass of Zn(ClO$_{3}$)$_{2}$ is } \boxed{\textbf{378 g}}

5 0
3 years ago
What is the mass, in grams, 6.5 mol of sodium nitrate (nano3)? please show all work?
ladessa [460]
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The atomic mass of sodium (Na) is = 22.98 
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The atomic mass of oxygen (O) is = 15.99  
The sodium nitrate (NaNO3) consists of the atomic masses of Na+N+(O)3 = 85 grams  
Therefore, the mass of 6.5 mol of sodium nitrate is = 6.5 * 1 mol of NaNO3 
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6 0
3 years ago
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aivan3 [116]

Answer:

Explanation:

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7 0
3 years ago
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