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3 years ago

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Which equations shows the complete dissociation of a strong base?

1 answer:

tensa zangetsu [6.8K]3 years ago

4 0

The correct answer is the fourth option. The complete dissociation of a strong base is BOH + h20 -> B+ + OH- + H20 since this is the only base from the choices given. A base is a substance that accepts hydrogen ions.

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Throughout the reflection, make sure you have a copy of the Student Guide and your data tables. Use the drop-

zalisa [80]

Answer: 1. Mass and type of solution

2. Type of material

3. Temperature

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3 years ago

Read 2 more answers

Some SO2 and O2 are mixed together in a flask at 1100 K in such a way ,that at the instant of mixing, their partial pressures ar

kakasveta [241]

Answer:

The answer is " $\bold{0.525\ \ atm^{-1}}$ "

Explanation:

Given equation:

$2SO_2(g) + O_2(g) \leftrightharpoons 2SO_3(g)$

Given value:

$\Delta rH =-198.2 \ \ \frac{KJ}{mol}$

$Kp=1100 \ K$

$\Delta x = 2-(2+1)\\\\$

$= 2-(2+1)\\\\= 2-(3)\\\\= -1$

$\left\begin{array}{cccc}I\ (atm)&1&0.5&0\\C\ (atm)&2x&-x&2x\\E\ (atm) &1-2x&0.5-x&2x\end{array}\right$

calculating the total pressure on equilibrium= $(1-2x)+(0.5-x)+2x \ atm\\\\$

$= 1-2x+0.5-x+2x\\\\= 1+0.5-x\\\\=1.5-x\\$

$\therefore \\\\\to 1.50-x= 1.35 \\\\\to 1.50-1.35= x\\\\\to 0.15= x\\\\ \to x= 0.15\\\\$

calculating the pressure in $So_2$ :

$= (1-2 \times 0.15)$

$= 1-0.30 \\\\ =0.70 \ atm$

calculating the pressure in $O_2$ :

$= (0.5- 0.15)\\\\= 0.35 \ atm \\$

calculating the pressure in $So_3$ :

$= (2 \times 0.15)\\\\= (.30) \ atm \\\\$

Calculating the Kp at 1100 K:

$= \frac{(Pressure(So_3))^2}{(Pressure(So_2))^2 \times Pressure(O_2)}\\\\= \frac{0.30^2}{0.70^2 \times 0.35}\\\\= \frac{0.30 \times 0.30 }{0.70\times 0.70 \times 0.35}\\\\= \frac{0.09 }{0.49\times 0.35} \\\\= \frac{0.09 }{0.1715} \\\\= 0.5247 \ \ or \ \ 0.525 \ \ atm^{-1} \\\\$

4 0

4 years ago

What is a likely oxidation<br> state of Chlorine?<br> a)-1<br> b) 7<br> C) -7<br> d) +1

Alenkasestr [34]

Answer: a) -1

Explanation:

6 0

4 years ago

The following reaction has Kp = 109 at 25°C. 2 NO(g) + Br2(g) equilibrium reaction arrow 2 NOBr(g) If the equilibrium partial pr

kati45 [8]

<u>Answer:</u> The equilibrium partial pressure of NO is 0.0034 atm

<u>Explanation:</u>

For the given chemical equation:

$NO(g)+Br_2(g)\rightleftharpoons 2NOBr(g)$

The expression of $K_p$ for above equation follows:

$K_p=\frac{(p_{NOBr})^2}{p_{NO}\times p_{Br_2}}$

We are given:

Equilibrium partial pressure of $Br_2$ = 0.0159 atm

Equilibrium partial pressure of NOBr = 0.0768 atm

$K_p=109$

Putting values in above equation, we get:

$109=\frac{(0.0768)^2}{p_{NO}\times 0.0159}\\\\p_{NO}=0.0034atm$

Hence, the equilibrium partial pressure of NO is 0.0034 atm

3 0

3 years ago

What are physical properties of Cobalt Silicate ?

seraphim [82]

Answer:

Some of the properties of cobalt silicate include:

It occurs as a crystal with red- violet type colour.

The shape of the cobalt silicate crystal is orthorhombic.

The molecular weight of cobalt silicate is 209.95.

The melting temperature of Cobalt Silicate is 1618 degrees Celsius.

The density of Cobalt Silicate is 4.63 grams per centimetre cube.

Cobalt Silicate can serve as a semi-conductor.

8 0

3 years ago