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4 years ago

An electric circuit can have no current when a switch is ________

Chemistry

2 answers:

Bond [772]4 years ago

7 0

An electric circuit can have no current when a switch is open. that is the correct answer.

klasskru [66]4 years ago

3 0

<h3><u>Answer;</u></h3>

Open

An electric circuit can have no current when a switch is <u>open</u>.

<h3><u>Explanation;</u></h3>

<em><u>An electric circuit is a path in which electrons from a voltage or current source flow. </u></em>
Electric switches are used to connect and break the flow of connectivity or flow of electrons in a circuit. A switch makes it easy to open or close an electrical circuit, turning the flow of electricity on or off.
<em><u>When a switch is closed the circuit is closed and thus the flow of current is on while when the switch is open, the circuit is open, and therefore there will be no flow of current in the circuit.</u></em>

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Relate the number of protons in the nucleus of an atom to the properties of matter.

Sauron [17]

Answer:

The number of electrons, in turn, determines the chemical properties of the atom. Protons contribute to the mass of an atom and provide the positive charge to the nucleus. The number of protons also determines the identity of the element

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4 years ago

How many formula units of lead (IV) phosphate in 1.75g

Iteru [2.4K]

1.05 x 10 to the 21 power formula units of lead (IV) phosphate

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3 years ago

Consider the above unbalanced equation. What volume of CO2 is produced at 270. mm Hg and 38.5°C when 0.820 g of C4H8 reacts with

irinina [24]

Answer:

The volume of CO2 is 4.20 L

Explanation:

Step 1: Data given

Pressure = 270 mm Hg = 260 /760 = 0.355263 atm

Temperature : 38.5 °C = 311.65 K

Mass of C4H8 = 0.820 grams

Step 2: The balanced equation

C4H8 + 6O2 → 4CO2 + 4H2O

Step 3: Calculate moles C4H8

Moles C4H8 = mass C4H8 / molar mass C4H8

Moles C4H8 = 0.820 grams / 56.11 g/mol

Moles C4H8 = 0.0146 moles

Step 4: Caalculate moles CO2

For 1 mol C4H8 we need 6 moles O2 to produce 4 moles CO2 and 4 moles H2O

For 0.0146 moles we'll have 4*0.0146 = 0.0584 moles CO2

Step 6: Calculate Volume CO2

p*V = n*R*T

V = (n*R*T) /p

⇒ with V = the volume of CO2 = TO BE DETERMINED

⇒ with n = the moles of CO2 = 0.0584 moles

⇒ with R = the gas constant = 0.08206 L*atm / mol*K

⇒ with T = The temperature = 311.65 K

⇒ with p = the pressure = 0.355263 atm

V = (0.0584 * 0.08206 * 311.65) / 0.355263

V = 4.20 L

The volume of CO2 is 4.20 L

8 0

3 years ago

CHEM HELP ASAP!! <br><br> What mass of H2 would be needed to produce 208 kg of methanol?

Eddi Din [679]

So if we use the equation:

$CO+2H_{2}$ → $CH_{3}OH$

We can then determine the amount of $H_{2}$ needed to produce 208 kg of methanol.

So let's find out how many moles of methanol 208 kg is:

Methanol molar weight = 32.041g/mol

So then we can solve for moles of methanol:

$208kg*\frac{1,000g}{1kg} *\frac{1mol}{32.041g} =6,491.68mol$

So now that we have the amount of moles produced, we can use the molar ratio (from the balanced equation) of hydrogen and methanol. This ratio is 2:1 hydrogen:methanol.

Therefore, we can set up a proportion to solve for the moles of hydrogen needed:

$\frac{2}{1} =\frac{x}{6,491.68}$

$x=12,983.36mol$

So now that we have the number of moles of $H_{2}$ that are produced, we can then use the molar weight of hydrogen to solve for the mass that is needed:

$12,983.36mol*\frac{2.016g}{1mol} =26,174.45g_H_{2}$

Therefore, the amount of diatomic hydrogen ( $H_{2}$ ) that is needed to produce 208kg of methanol is $2.62x10^{4}$ g.

3 0

3 years ago

How do I calculate this slope?

zmey [24]

Rise over run. Just like you have set up. If you plotted the data points subtract (y2-y1)/(x2-X1)

6 0

4 years ago