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4 years ago

Can Someone Help Me With This?

Physics

1 answer:

Stels [109]4 years ago

4 0

$\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{bases}{parallel~sides}\\ h=height\\[-0.5em] \hrulefill\\ a=3\\ b = 9\\ A=84 \end{cases}\implies 84=\cfrac{h(3+9)}{2}\implies 84=\cfrac{h(12)}{2} \\\\\\ 84=6h\implies \cfrac{84}{6}=h\implies 14=h$

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Some ideal gas is constrained in the V"part of anadiabatic container of volume V" V$. The rest of the container is vacuum. When

solmaris [256]

Answer:

Using the log combination rules to reduce the famous Sakur-Tetrode equation, The change in entropy is given as:

∆S = NK*ln(V"V$/V").

Where V"V$ is final Volume (Vf) after constraint's removal,

V" is Initial Volume (Vi) before constraint's removal.

Temperature (T) is constant, Internal Energy, U is constant, N and K have their usual notations

Explanation:

Given in the question, the container is an adiabatic container.

For an adiabatic contain, it does not permit heat to the environment due to its stiff walls. This implies that the Internal Energy, U is kept constant(Q = U). The temperature is also constant (Isothermal). Thus, the famous Sakur-Tetrode equation will reduce to ∆S = NK* In(Vf/Vi).

Vf is the volume after the constraint is removed(Vf = V"V$). Vi is the volume occupied before the constraint is removed (Vi = V")

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3 years ago

A fast moving vehicle travelling at a speed of 25.4 m/s comes up behind another vehicle which is

ale4655 [162]

Answer:

a = 6.1 m / s²

Explanation:

For this kinematics exercise, to solve the exercise we must set a reference system, we place it in the initial position of the fastest vehicle

Let's find the relative initial velocity of the two vehicles

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v₀ = 25.4 - 13.6

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x = v₀ t + ½ a t²

The faster vehicle has an initial speed relative to the slower vehicle, therefore it is as if the slower vehicle were stopped, so the distance that must be traveled in a fast vehicle to reach this position is

x = 11.4 m

let's use the expression

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how the vehicle stops v = 0

a = v₀² / 2x

a = $\frac{11.8^2}{2 \ 11.4}$

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this velocity is directed to the left

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Answer:

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Explanation: