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3 years ago

Urgent pls help

Physics

2 answers:

Firdavs [7]3 years ago

8 0

Answer:

the answer is d. because water has a higher specific heat capacity than sand

Ede4ka [16]3 years ago

3 0

In my opinion,Sand has more specific heat than water.

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If the sum of the external forces on an object is zero, then the sum of the external torques on it

Zarrin [17]

Answer:

True.

Explanation:

If the sum of the external forces on an object is zero, then the sum of the external torques on it must also be zero.

The net external force and the net external torque acting on the object have to be zero for an object to be in mechanical equilibrium.

Hence, the given statement is true.

5 0

3 years ago

A ball with a mass of 0.585 kg is initially at rest. It is struck by a second ball having a mass of 0.420 kg , initially moving

Y_Kistochka [10]

Answer:

a) $(v_1)=0.3989m/s$

b) $\theta_1=80.5 \textdegree$

c) $K.E=0.036J$

Explanation:

From the question we are told that:

Initial speed of 1st ball $u_{1}=0 m/s$

Mass of 1st ball $m_1=0.585kg$

Mass of 2nd ball $m_2=0.420kg$

Initial speed of 2nd ball $u_{2}=0.270 m/s$

Final speed of 2nd ball $v_{2}=0.220 m/s$

Angle of collision $\angle=36.9 \textdegree$

Generally the equation for law of conservation is mathematically given by

$m_1u_1+m_2u_2=m_1v_1^2+m_2v_2^2$

The final velocity $v_1$ is given as

$0+(0.420)(0.270)=(0.585)(v_1)^2+(0.420)(0.220)^2$

$(v_1)^2=\frac{(0.420)(0.270)-(0.420)(0.220)^2}{0.585}$

$(v_1)^2=0.1591$

$(v_1)=0.3989m/s$

Generally the equation for law of conservation is mathematically given by

$m_1u_1+m_2u_2=m_1v_1cos\theta_1+m_2\theta_2$

$0+(0.420)(0.270)=(0.585)(1.511)cos\theta_1+(0.420)(0.220)cos36 \textdegree$

$cos\theta_1= \frac{(0.420)(0.270)-(0.420)(0.220)cos36 \textdegree}{(0.585)(0.3989)}$

$cos\theta_1=0.1656$

$\theta_1=80.5 \textdegree$

Generally the equation for kinetic energy is mathematically given by

$K.E=\frac{1}{2} mv^2$

1st Ball

$K.E=\frac{1}{2} (0.585)(0.3989)^2$

$K.E=0.0465J$

2nd ball

$K.E=\frac{1}{2} (0.420)(0.220)^2$

$K.E=0.101J$

Therefore the change in the total kinetic energy of the two balls as a result of the collision is

$0.101-0.0465$

$K.E=0.036J$

3 0

3 years ago

A proton is confined within an atomic nucleus of diameter 3.60 fm. part a estimate the smallest range of speeds you might find f

Cerrena [4.2K]

The answer for this problem would be:
Assuming non-relativistic momentum, then you have:
ΔxΔp = mΔxΔv = h / (4)
Δv = h / (4πmΔx)
m ~ 1.67e-27 h ~ 6.62e-34,Δx = 4e-15 -->
Δv ~ 6.62e-34 / (4π * 1.67e-27 * 4e-15) ~ 7,886,270 m/s ~ 7.89e6 m/s
That's about 1% of the speed of light, the assumption that it's non-relativistic.

3 0

3 years ago

Two balls have masses 18 kg and 47 kg. The 18 kg ball has an initial velocity of 76 m/s (to the right) along a line joining the

BigorU [14]

Answer:

The final velocity of 18 kg ball is $V_{2}$ = 42.09 $\frac{m}{sec}$

Explanation:

Mass of first ball $m_{1}$ = 18 kg

Mass of second ball $m_{2}$ = 47 kg

Initial velocity of 18 kg ball $V_{1}$ = 76 $\frac{m}{sec}$

Initial velocity of 47 kg ball = 0

Final velocity of 18 kg ball $V_{2}$ = ??

Final velocity of 18 kg ball is given by the formula

$V_{2}$ = $\frac{2 m_{1} V_{1} }{m_{1} + m_{2} }$

Put all the values in above formula we get

$V_{2}$ = 2 × 18 × $\frac{76}{65}$

$V_{2}$ = 42.09 $\frac{m}{sec}$

Thus, the final velocity of 18 kg ball is $V_{2}$ = 42.09 $\frac{m}{sec}$

3 0

3 years ago

How does a seat belt stop your body from moving in a forward motion in a car?

stiks02 [169]

D, when a moving car suddenly stops, your body is still moving forward until the seatbelt stops you.

When things move, there is always friction. It's what makes cars move in the first place. The inside of the car doesn't move, however the wheels on the car are moving at a rapid pace. When the car stops violently, everything inside the car is thrown. The seat belt acts as a safety precaution if an accident happens.

Mark brainliest?

5 0

3 years ago