Answer:
F = ⅔ F₀
Explanation:
For this exercise we use Coulomb's law
F = k q₁q₂ / r²
let's use the subscript "o" for the initial conditions
F₀ = k q² / r²
now the charge changes q₁ = q₂ = 2q and the new distance is r = 3 r
we substitute
F = k 4q² / 9 r²
F = k q² r² 4/9
F = ⅔ F₀
Acceleration occurs whenever the direction or the speed changes
Positively charged protons in the nucleus of the gold atom .... rutherford scattering ???
Answer:
Haven't done this but I think it will increase by 73.29% not too anyone correct me if I'm worng
