Question

Refer to the rectangle at the right. Suppose the side lengths are doubled. a. Find the percent of change in the perimeter b. Find the percent of change in the area

Answer 1

Answer:

400% area and 200% perimeter

Step-by-step explanation:

Given is a picture of a rectangle.  (i.e. opposite sides are equal and all angles equal to 90 degrees)

We know for any rectangle with length l and width, w

Area of rectangle = lw and

Perimeter of rectangle = 2(l+w)

Suppose the side lengths are doubled

Now length = 2l and width = 2w

New ARea = $2l*2w\\=4lw$

i.e. 400% times is the new area.

New perimeter = $2(2l+2w) =4(l+w)$

New perimeter is 200% times the old perimeter.