Now consider machining jamming caused by both defective parts jamming and station malfunction. Assume component lot quality is a
t the level of 1/4 percent defective, what is the production rate? Can the production quota of 2,500 units per eight-hour shift be met? What is the percent downtime? What is the efficiency of this line? What is the throughput time?
1 answer:
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Answer
The answer and procedures of the exercise are attached in the following archives.
Explanation
You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.
Answer:
a. radius = 0.0006m = 0.6mm and length =0.393m = 393mm
b. frequency =377.86Hz
Explanation:
Given:
mass of steel= 4g = 0.004kg
density of steel = 7890kg/m3
tensile stress of steel 7.0x10⁸
tension load =900N
from the density, we will calculate for the Volume of the steel string
density = mass/volume
volume = mass/density = 0.004/7890 = 5.07 x 10⁻⁷ m³
from the tensile stress will can get the maximum base Area of the string ,
tensile stress = load/area =
7x10⁸ = 900/A
A = 900/7x10⁸ = 1.29x10⁻⁶ m²
Area = πr²
area/pi = 4.105x10-7
radius = 0.0006m = 0.6mm
volume = Area x length
length = vol/area =(5.07 x 10⁻⁷ m³)/1.29x10⁻⁶ m² = 0.393m
b. the highest possible frequency is given by:
F =
where T= tension, m=mass, L=length
F =
= 297.04/0.786
frequency =377.86Hz