Solve this equation: –9h – 6 + 12h + 40 = 22.

2 answers:

6 0

Let's solve your equation step-by-step.−9h−6+12h+40=22Step 1: Simplify both sides of the equation.−9h−6+12h+40=22Simplify: (Show steps)3h+34=22Step 2: Subtract 34 from both sides.3h+34−34=22−343h=−12Step 3: Divide both sides by 3.3h3=−123h=−4Answer:h=−4

svlad2 [7]3 years ago

5 0

Combine like terms to get 3h + 34 = 22, subtract 34 from 22 to get 3h = -12, divide by 3 on both sides to get h= -4<span>

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Condition is met on the first three days and green light on the fourth day: $(0.5 \times 0.5 \times 0.5) \times 0.5$ .

To meet the condition on the fifth day, there needs to be a yellow light. The probability that the condition is met on the first four days and on the fifth day will be $(0.5 \times 0.5 \times 0.5 \times 0.5) \times 0.1 = 0.5^{4} \times 0.1$ .

To meet the condition on the sixth day, all prior days should meet the conditions. Besides, there needs to be a red light on the sixth day. $(0.5^{4} \times 0.1) \times 0.4$

Seventh day: $(0.5^{4} \times 0.1 \times 0.4 ) \times 0.4$
Eighth day: $(0.5^{4} \times 0.1 \times 0.4^2 ) \times 0.4$
Ninth day: $(0.5^{4} \times 0.1 \times 0.4^3 ) \times 0.4$
Tenth day: $(0.5^{4} \times 0.1 \times 0.4^4 ) \times 0.4 = 0.5^{4} \times 0.1 \times 0.4^{5}$

The question asks that the condition be met on all ten days. As a result, the probability of meeting the condition will be equal to the probability on the tenth day: $0.5^{4} \times 0.1 \times 0.4^{5} = 6.4\times 10^{-5} = 0.000064 = 0.0064\%$ .