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levacccp [35]
3 years ago
11

The graph of F(x) shown below resembles the graph of G(x) = x ^ 2 but it has been changed somewhat . Which of the following coul

d be the equation of

Mathematics
1 answer:
Lorico [155]3 years ago
5 0

Answer:

f(x) = 3x^{2} + 2

Step-by-step explanation:

I think your question missed key information, allow me to add in and hope it will fit the orginal one because I answered this question once in Brainly as well. Please have a look at the attached photo.

My answer:

  • Given G(x) =  x^{2}

As we can see, the graph of f(x) is 2 units above the graphof g(x) in vertical (vertical shift)

=> f(x) = ax^{2} + 2

As you can see, the graph of f(x) is stretched vertically by a dilation factor of 3  and there is no reflection, so a= 3

=> the  equation of f(x) is:  f(x) = 3x^{2} + 2  

Hope it will find you well.

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21. Estimate the annual wages for a cashier who earns $11<br> an hour.
DerKrebs [107]

Answer:

~22,000 /yr

Step-by-step explanation:

52 weeks/yr

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3 0
3 years ago
A ramp to a building has a height of 4 feet and the angle of elevation is 33 defrees. How long is the ramp?
sladkih [1.3K]
Height=4 ft
angle=33 degrees
My tip first is to draw it out. Draw an acute angle opening up to a building forming a triangle. Inside of the vertex of the acute angle is the degree 33 and the height of the building is 4 ft. So, use trig! Do you have a calculator? Opposite over hypotenuse is Sine. (SOH CAH TOA). (4)/(sin(33)). which equals 7.34 ft as your height! Hope this helped!
5 0
3 years ago
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Tpy6a [65]

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5 0
2 years ago
Lin ran 2 3/4 miles in 2/5 of an hour, Noah ran 8 2/3 miles in 4/3 of an hour, how far would Lin run in 1 hour?
Marizza181 [45]

Answer:

6\frac{7}{8}\ miles

Step-by-step explanation:

Given that Lil's distance in 2/5 hrs is 2 3/4hrs

-Let x be the distance ran in 1 hr.

#We equate and cross multiply to solve for x as follows:

\frac{2}{5}\ hrs=2\frac{3}{4}\\1\ hr=x\\\\\therefore x=2\frac{3}{4}/\frac{2}{5}\\\\=6\frac{7}{8}\ miles

Hence, Lil can run 6 7/8 miles in 1 hr.

5 0
3 years ago
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