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7. A gas-filled weather balloon with a volume of 65.0 L is released at sea-level conditions of

Galina-37 [17]

The balloon will reach its maximum volume and it will burst.

Given:

A weather balloon at sea level, with gas at 65.0 L volume, 745 Torr pressure, and 25C temperature.
When the balloon was taken to an altitude at which temperature was 25C and pressure was 0.066atm its volume expanded.
The maximum volume of the weather balloon is 835 L.

To find:

Whether the weather balloon will reach its maximum volume or not.

Solution:

The pressure of the gas in the weather balloon at sea level = $P_1=745 torr$

$1 atm = 760 torr\\P_1=745 torr=\frac{745}{760} torr = 0.980 atm$

The volume of the weather balloon at sea level = $V_1=65.0L$

The temperature of the gas in the weather balloon at sea level:

$T_1=25^oC=25+273.15 K=298.15 K$

The balloon rises to an altitude.

The pressure of the gas in the weather balloon at the given altitude:

$P_2=0.066atm$

The volume of the weather balloon at the given altitude = $V_2=?$

The temperature of the gas in the weather balloon at the given altitude:

$T_1=25^oC=25+273.15 K=298.15 K$

Using the Combined gas law:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\\\frac{0.980 atm\times 65.0L}{298.15 K}=\frac{0.066atm\times V_2}{298.15K}\\V_2=\frac{0.980 atm\times 65.0L\times 298.15K}{0.066atm\times 298.15 K}\\=965L$

The maximum volume of the weather balloon= V = 835 L

$V < V_2$

The volume of the weather balloon at a given altitude is greater than its maximum volume which means the balloon will reach its maximum volume and it will burst.

Learn more about the combined gas law:

brainly.com/question/13154969?referrer=searchResults

brainly.com/question/936103?referrer=searchResults

4 0

3 years ago

Which objects refract light? (Select all that apply.)

Free_Kalibri [48]

Concave mirrors, magnifying lens... sorry not sure about the rest

3 0

3 years ago

Read 2 more answers

The yearly amounts of carbon emissions from cars in Belgium are normally distributed with a mean of 13.9 gigagrams per year and

zavuch27 [327]

Answer:

The correct option is;

c. 0.167

Explanation:

The parameters given are;

The mean, μ = 13.9 Gigagrams/year

The standard deviation, σ = 5.8 Gigagrams/year

The z-score formula is given as follows;

$z = \dfrac{x - \mu }{\sigma }$

Where:

x = Observed score = 11.5 Gigagrams/year

We have;

$z = \dfrac{11.5 - 13.9 }{5.8 } = \dfrac{-2.4 }{5.8 } = 0.4138$

From the z-score table relations/computation, the probability (p-value) = 0.6605

Where:

x = Observed score = 14 Gigagrams/year

We have;

$z = \dfrac{14- 13.9 }{5.8 } = \dfrac{0.1}{5.8 } = 0.01724$

From the z-score table relations/computation, the probability (p-value) = 0.4931

Therefore, the probability, $p_{ca}$ , that the amount of carbon emissions from cars in Belgium for a randomly selected year are between 15.5 Gigagrams/year and 14 Gigagrams/year = The area under the normal curve bounded by the p-values for the two amounts of carbon emission

Which gives;

$p_{ca}$ = 0.6605 - 0.4931 = 0.1674 ≈ 0.167

Therefore, the correct option is c. 0.167.

4 0

4 years ago

What type of bond is most likely to form between atoms with a difference in

ser-zykov [4K]

Answer:Polar covalent bond

Explanation:Polar covalent bonds form between atoms with an electronegativity difference between 0.5 and 1.7.

3 0

3 years ago

How many moles of sodium atoms do you have if you have 5.60 ~

Papessa [141]

Answer:

0.93 mol

Explanation:

Given data:

Number of moles of Na atom = ?

Number of atoms = 5.60× 10²³

Solution:

Avogadro number:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance. The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

5.60× 10²³ atoms × 1 mol / 6.022 × 10²³ atoms

0.93 mol

3 0

3 years ago