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nata0808 [166]
3 years ago
9

What is the similarity ratio for the above triangles?

Mathematics
1 answer:
ololo11 [35]3 years ago
7 0

Answer:

3.71...

Step-by-step explanation:

You have to divide one side by the other

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The sum of 9 and k minus 17
Gelneren [198K]
If you mean 9k-7 then you have to divide if not then I don’t really get the question lol
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3 years ago
A stuntman jumping off a 20-m-High building is modeled by the equation h=20-5t^2, where t is the same in seconds. A high-speed c
Alchen [17]

Answer: 1\leq t\leq \sqrt{2}


Step-by-step explanation:

1. You know that the high-speed camera is ready to film him between 15 meters and 10 meters above the ground.

2. The problem gives you the following equation:

h=20-5t^{2}

3. Therefore, you must calculate the time when h=15 and when h=10, as following:

h=15\\15=20-5t^{2}\\5t^{2}=5\\t=\sqrt{1}\\t=1  


h=10\\10=20-5t^{2}\\5t^{2}=10\\t=\sqrt{2}

4. Therefore, the answer is:

1\leq t\leq \sqrt{2}

3 0
4 years ago
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SOVA2 [1]

Answer:

3 + ( - 4) \\ 3 - 4 =  - 1

<h3><u>PLEASE</u><u> MARK</u><u> ME</u><u> BRAINLIEST</u><u>.</u></h3>
5 0
3 years ago
How would you describe the slice that created the square cross section an this cake
Bas_tet [7]

Answer: Parallel to the base.


Step-by-step explanation:

1. By definition a cross section is the intersection of a plane and a body of three dimensions.

2. As you can see inf the figure attached in the problem, the square cross section does not touch the base of the cake, then, by definition the slice that created the square cross section on the cake is parallel to the base of the cake.

3. Therefore, the answer is the third option.

3 0
4 years ago
Read 2 more answers
Haven't run across one with three terms. help? preferably explain how you got the answer too!!​
const2013 [10]

Answer:

c^3 + c^2 - 7c + 20

Step-by-step explanation:

First, expand the expression using distributive property.

c^2(c+4) - 3c(c+4) + 5(c+4)

c^3 + 4c^2 - 3c^2 - 12c + 5c + 20

Lastly, simplify like terms.

c^3 + c^2 - 7c + 20

5 0
3 years ago
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