All categories

3 years ago

Round 9,254 to the nearest hundred

Mathematics

2 answers:

Daniel [21]3 years ago

8 0

9300 would be the nearest hundred. Since 54 is over 50 you round up

Andrew [12]3 years ago

5 0

Since 5 is above 4, we move the number infront of 5 which is 2 so, the answer is 9,300. You might not understand me

You might be interested in

A ramp is placed from a ditch to a main road 2ft. above the ditch. If the length of the ramp is 12ft, how far away is the bottom

Nadusha1986 [10]

See attached picture for solution:

6 0

4 years ago

Can Some one please help me on these math questions I'll give 20 points please

MArishka [77]

Answer:

☐ -2 < 2x + 4

☐ -3x - 2 > 5

Step-by-step explanation:

-3x - 2 > 5

+ 2 + 2

___________

-3x > 7

___ ___

-3 -3

x < -2⅓ [Anytime you divide or multiply by a negative, reverse the inequality symbol.]

-2 < 2x + 4

-4 - 4

___________

-6 < 2x

__ ___

2 2

-3 < x

If you plug in -3 for x < -2⅓, you will see that it is a genuine statement because the more higher a negative gets, the lesser the integer will be, so in this case, -3 IS less than -2⅓.

I am joyous to assist you anytime.

** If it is not multi-select, then choose -2 < 2x + 4.

4 0

3 years ago

Ingrid bought a laptop that was 30% off the regular price of $1,050. If a 7% sales tax was added to the cost of the laptop, what

melamori03 [73]

Her total price would be $786.45

5 0

3 years ago

Suppose that S is the set of successful students in a classroom, and that F stands for the set of freshmen students in that clas

lora16 [44]

Answer:

b) 24

Step-by-step explanation:

We solve building the Venn's diagram of these sets.

We have that n(S) is the number of succesful students in a classroom.

n(F) is the number of freshmen student in that classroom.

We have that:

$n(S) = n(s) + n(S \cap F)$

In which n(s) are those who are succeful but not freshmen and $n(S \cap F)$ are those who are succesful and freshmen.

By the same logic, we also have that:

$n(F) = n(f) + n(S \cap F)$

The union is:

$n(S \cup F) = n(s) + n(f) + n(S \cap F)$

In which

$n(S \cup F) = 58$

$n(s) = n(S) - n(S \cap F) = 54 - n(S \cap F)$

$n(f) = n(F) - n(S \cap F) = 28 - n(S \cap F)$

$n(S \cup F) = n(s) + n(f) + n(S \cap F)$

$58 = 54 - n(S \cap F) + 28 - n(S \cap F) + n(S \cap F)$

$n(S \cap F) = 24$

So the correct answer is:

b) 24

3 0

4 years ago

Where can the denominator be found in a fraction?

Anuta_ua [19.1K]

Down on the bottom, under the fraction line.

5 0

4 years ago

Read 2 more answers