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Ede4ka [16]
3 years ago
5

8 Base = _______________ Exponents = ________________

Mathematics
2 answers:
leonid [27]3 years ago
6 0
What do you mean 8 to the what power

Musya8 [376]3 years ago
5 0
8x8=64 so that's your base number and the exponent is 64x64=4096
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A bag of paper clips contains:
Zina [86]

Answer:

14 times

Step-by-step explanation: add all colors up for total which is 25

since 7 out of the 25 total paper clips are yellow you would have a 7/25 chance of getting yellow after 1 pick.

since you pick and replace 50 times do  (7/25) X 50 which gives you 14 times yellow will be drawn.

7 0
2 years ago
Read 2 more answers
Please answer this I need help asap
Yanka [14]

Answer:

(12, 48 )

Step-by-step explanation:

Given the 2 equations

y = 5x - 12 → (1)

y = 3x + 12 → (2)

Substitute y = 5x - 12 into (2)

5x - 12 = 3x + 12 ( subtract 3x from both sides )

2x - 12 = 12 ( add 12 to both sides )

2x = 24 ( divide both sides by 2 )

x = 12

Substitute x = 12 into either of the 2 equations and evaluate for y

Substituting into (2)

y = 3(12) + 12 = 36 + 12 = 48

solution is (12, 48 )

8 0
3 years ago
What is GCF and LCM of -5 and 56? Please Help! Will give Brainliest!
Nookie1986 [14]

Answer:

The GCF is 1 and the LCM 280

Step-by-step explanation:

I did this on a test and got it right

4 0
3 years ago
Read 2 more answers
Solve 765/14 and write your answer in terms of a mixed number (please use this format: 75 3/5). *
kozerog [31]

the answer is 54 9/14

because Divide using long division. The whole number portion will be the number of times the denominator of the original fraction divides evenly into the numerator of the original fraction, and the fraction portion of the mixed number will be the remainder of the original fraction division over the denominator of the original fraction.

6 0
3 years ago
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Q(x)=x^3+ax^2+2b is divided by (x-3) and has a remainder of 4. Find the values of "a" and "b"​
Sati [7]

Answer:

Let p(x) = x3 + ax2 + bx +6

(x-2) is a factor of the polynomial x3 + ax2 + b x +6

p(2) = 0                                                                                      

p(2) = 23 + a.22 + b.2 +6 =8+4a+2b+6 =14+ 4a+ 2b = 0

7 +2 a +b = 0

b = - 7 -2a -(i)                                                                              

x3 + ax2 + bx +6 when divided by (x-3) leaves remainder 3.

p(3) = 3                                                                                      

p(3) = 33 + a.32 + b.3 +6= 27+9a +3b +6 =33+9a+3b = 3

11+3a +b =1 => 3a+b =-10 => b= -10-3a -(ii)                                    

Equating the value of b from (ii) and (i) , we have

(- 7 -2a) = (-10 - 3a)

a = -3                                                                                          

Substituting a = -3 in (i), we get

b = - 7 -2(-3) = -7 + 6 = -1

Thus the values of a and b are -3 and -1 respectively.

Step-by-step explanation:

4 0
3 years ago
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